Answer: If the wall is 300 meters long, the dimensions of the fence with the maximum area will be 300 × 150 = 45000 m²
Step-by-step explanation:
try combinations in a chart
190 × (600-190)/2 = 38950 = 190 × 205 increasing area
200 × (600-200)/2 = 40000 = 200 × 200
220 × (600-220)/2 = 41800 == 220 × 190
240 × (600-240)/2 = 43200 == 240 × 180
260 × (600-260)/2 = 44200 == 260 × 170
280 × (600-280)/2 = 44800 . == 280 × 160
<u>300 × (600-300)/2 = 45000 == 300 × 150</u> Maximum Area
310 × (600-310)/2 = 44950 . == 310 × 145 decreasing area
320 × (600-320)/2 = 44800 . == 320 × 140
Answer: where is the homework that is needing help
Answer:
y = 2x + 2
Step-by-step explanation:
for each rise of 4 in y
there is a run of 2 in x
m = rise/run
m = 4/2
m = 2
when x = 0, y = 2
therefor the y-intercept, b = 2
y = mx + b
y = 2x + 2
The mean would be np, which here would be (6)(0.36) = 2.16.
Answer:
same
Step-by-step explanation: im too lazy