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2 years ago

10

Describe the graph of the system of inequalities:

1 answer:

Mila [183]2 years ago

4 0

Answer:

i hope its right

Step-by-step explanation:

give me brainliest answer.

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Help Me quick please!!!

Musya8 [376]

Let the width of room be =x mtrs

Then the length is x+2 mtrs

As Perimeter = 2(l+b) = 2(x+x+2)

16 = 2 ( 2x+2)

16/2 = 2x +2

8=2x+2

2x= 8-2 = 6

x = 6/2 =3 mtrs

Therefore width of the room is 3 mtrs

7 0

3 years ago

Read 2 more answers

Adding fractions 1/6+2/3=

mars1129 [50]

Answer:

$\frac{5}{6}$

$\frac{1}{6} + \frac{2}{3}$ is equivalent to $\frac{1}{6} + \frac{4}{6}$ .

This is because $\frac{2}{3}=\frac{4}{6}$

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

<em>Now what do we do? We add!</em>

$\frac{1}{6} + \frac{4}{6} =\frac{5}{6}$

This is because 4 + 1 = 5.

Your answer is $\frac{5}{6}$ .

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

8 0

3 years ago

Read 2 more answers

WILL GIVE A BRAINLIEST!! PLEASE HELP!!

tia_tia [17]

<span>3^5 * 6^-6 / 3^3 * 6^-4
= 3^2 6^-2
= 3^2 / 6^2
= 9/36
=1/4

answer
</span><span>C.
1/4</span>

5 0

2 years ago

2 + 1/3t = 1 + 1/4t<br> Please help me

navik [9.2K]

Answer:

<h3>r =-12</h3>

Step-by-step explanation:

$2 + 1/3t = 1 + 1/4t\\\\2+\frac{1}{3}t=1+\frac{1}{4}t\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\2+\frac{1}{3}t-2=1+\frac{1}{4}t-2\\\\Simplify\\\frac{1}{3}t=\frac{1}{4}t-1\\\\\mathrm{Subtract\:}\frac{1}{4}t\mathrm{\:from\:both\:sides}\\\frac{1}{3}t-\frac{1}{4}t=\frac{1}{4}t-1-\frac{1}{4}t\\\\Simplify\\\frac{1}{12}t=-1\\\\\mathrm{Multiply\:both\:sides\:by\:}12\\12\times\frac{1}{12}t=12\left(-1\right)\\\\\\Simplify\\r =-12$

8 0

3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago