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2 years ago

10

Describe the graph of the system of inequalities:

1 answer:

Mila [183]2 years ago

4 0

Answer:

i hope its right

Step-by-step explanation:

give me brainliest answer.

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Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20log%288%29%20%7D%7Blog%282%29%20%7D%20" id="TexFormula1" title=" \frac{ log(8)

brilliants [131]

Answer:

$\frac{log(8)}{log(2)} = 3$

Good luck friend, I really hope this helps ya :)

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2 years ago

You only want to buy photos in sizes that are similar rectangles for your new gallery wall in your home. Which size photos shoul

Svet_ta [14]

You'd want to buy the 4 by 5 and the 11 by 14 because if you times 4 by 3 and 5 by 3, the answer would be 12 by 15 which is the closet or the most similar pair

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3 years ago

Can someone help please!

GarryVolchara [31]

This is for the first one

6 0

2 years ago

What is the value of y??

vovikov84 [41]

Answer:

75

Step-by-step explanation:

5 0

3 years ago