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MariettaO [177]
3 years ago
5

What is the value of 9 in the number 59.533

Mathematics
2 answers:
hoa [83]3 years ago
8 0
First you have to label the other number , example : Ones, Tens, Hundreds
_______________________________________________________

5 9 . 5 3 3      | Start at the end , the number 3 , So it's 3= Ones , 3 , Tens , 5= Hundreds , There is a decimal so start over =  9= Ones 

The number Nine is just 9 , because it's in the ones place and if it's in the ones place most of the time it stays the same.

___________________________________________________

I really hope that my solutions and example helped you a lot , have a nice day :)




kati45 [8]3 years ago
5 0

The value of the digit 9 in 59.533 is \boxed{9{\text{ ones}}} or ones place.

Further explanation:

Explanation:

The whole numbers is the series of numbers that starts from zero.

The natural numbers are those numbers that start from one.

After decimal the first place is the tenth place, the second place is the hundredth and the third place is the thousandth.

The first digit from the right is the ones place, the second digit from the right is the tens place, the third digit from the right is the hundreds place, the fourth digit from the right is the thousands.

The number is59.533.

From the left the 5 is on the tens place, 9 is on the ones place, 5 is on the tenth place, 3 is on the hundredth place and 3 is on the thousandth place.

The value of the digit 9 in 59.533 is \boxed{9{\text{ ones}}} or ones place.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.  Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Decimals

Keywords: value, digit, place value, 9, tens, hundreds, 59.533, thousandth, ones, digit 9, place, base ten.

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\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

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