2 years ago

PLSSSS HELPPPPPPPP

Mathematics

2 answers:

galina1969 [7]2 years ago

8 0

Not a clue at all how u so this

Tasya [4]2 years ago

8 0

Its B
Because I took this before and I remember I passed the test by 100

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<img src="https://tex.z-dn.net/?f=4%284x-4%29%2Bx%2B4%3D-46" id="TexFormula1" title="4(4x-4)+x+4=-46" alt="4(4x-4)+x+4=-46" alig

muminat

Answer:

x=-2

Step-by-step explanation:

$4(4x-4)+x+4=-46\\16x-16+x+4=-46\\17x-16+4=-46\\17x-12=-46\\17x=-34\\x=-2$

8 0

2 years ago

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Help me out please lol

Arisa [49]

Answer:

b is the aswer

Step-by-step explanation:

5 0

3 years ago

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Divide the difference of 18 and 3 by the sun of 1 and 2

NikAS [45]

Okay.

(18-3)/(1+2) = 15/3 = 5

answer: 5

4 0

4 years ago

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Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo

Ilya [14]

Answer:

$x^6+3x^3+3+\dfrac{1}{x^3}$

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

$(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}$

4 0

4 years ago

Solve plss<br><br> -8r + 12 = 36

liubo4ka [24]

-8r + 12 = 36

- 8 r = 36 - 12

- 8r = 24

8r = - 24

r = - 24 / 8

r = - 3

4 0

2 years ago

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