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IRISSAK [1]
2 years ago
12

W

Mathematics
1 answer:
Ymorist [56]2 years ago
3 0

Answer

2

Step-by-step explanation:

The ratio of pigs to other animals would be 5:20, which is 1:4 simplified.

That means that the amount of pigs is a quarter of other animals.

1+4 = 5

10/5 =2

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What is the smallest subset of the square root of 100
aev [14]
=2x5
=10
If you have a certain type of calculator it could answer that question easy

3 0
3 years ago
HELP!!!!! I do not understand how to do this! Could someone please explain to me how I would solve this problem?
maks197457 [2]
Yeah man nearly there
3 0
3 years ago
PLEASE ANSWER THIS ASAP!!!!
Anit [1.1K]

Answer:

82 units

Step-by-step explanation:

7 x 3 = 21

21 x 2 = 42

7 x 2 = 14

14 x 2 = 28

2 x 3 = 6

6 x 2 = 12

42 + 28 + 12 = 82

7 0
3 years ago
Priority question
Ymorist [56]
Sixth grade:
7 | x x x x x x
8 | x x x x
9 |x x x x x x
A | x x x x . . . . . . . . where "A" is used to represent 10 tens (100)

7th grade:
5 | x x x x x
6 | x x x x x x x
7 | x x x x
8 | x x x x

The range (low, high) and median of the 6th grade scores are all higher than those of the 7th grade scores.

Based on visual inspection, Grade 6 appears to have the higher mean score.
6 0
3 years ago
Read 2 more answers
EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the perce
miss Akunina [59]

Answer:

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

Step-by-step explanation:

1) Data given and notation  

n=500 represent the random sample taken    

X represent the number of females in the U.S. labor force

\hat p=0.46 estimated proportion of females in the U.S. labor force

\alpha=0.05 represent the significance level (no given, but is assumed)    

z would represent the statistic    

p= population proportion of females in the U.S. labor force

2) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.46 - 1.96 \sqrt{\frac{0.46(1-0.46)}{500}}=0.416

0.46 + 2.58 \sqrt{\frac{0.46(1-0.46)}{500}}=0.504

On this case the calculated interval is not the given , but let's assume that the confidence interval is given by the statment: "United States Department of Labor find that 95% confidence interval for the proportion of females in the U.S. labor force is .357 to .443."

3) Correct interpretation

a. The margin of error for the true percentage of females in the U.S. labor force is between 35.7% and 44.3%.

False the confidence interval not conclude about the margin of error conclude about the true proportion.

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

True, the statement report the confidence level and the limits for the margin of error.

c. The percentage of females in the U.S. labro force is between 35.7% and 44.3%.

False, The statement is not correct because not reports the confidence level.

d. All sample of size 500 will yield a percentage of females in the U.S. labor force that falls within 35.7% and 44.3%

False the confidence interval is for the population proportion not just for the samples of size 500

e. None of these.

False, we have an option that is true.

8 0
3 years ago
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