What is the constant proportionality for the relationship on the graph

Mathematics

2 answers:

tankabanditka [31]3 years ago

5 0

<h3>Answer: Choice A) 3.5</h3>

Work Shown:

The point (8,28) is the furthest to the right on the graph. We have x = 8 and y = 28 pair up here. Divide the y over the x

y/x = 28/8 = 3.5

side note: the tickmarks on the y axis go up by 4 each time

svetoff [14.1K]3 years ago

3 0

Y/x =28/8=3.5
So A is the answer

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Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is <span>D. 12xy^2
</span>
$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

3 0

3 years ago

PLS HALPPPPP!!!!

andrey2020 [161]

Answer:

11.01

Step-by-step explanation:

3.78+4.51+2.72=11.01

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3 years ago

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