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alexandr1967 [171]
3 years ago
14

What is the constant proportionality for the relationship on the graph​

Mathematics
2 answers:
tankabanditka [31]3 years ago
5 0
<h3>Answer: Choice A) 3.5</h3>

Work Shown:

The point (8,28) is the furthest to the right on the graph. We have x = 8 and y = 28 pair up here. Divide the y over the x

y/x = 28/8 = 3.5

side note: the tickmarks on the y axis go up by 4 each time

svetoff [14.1K]3 years ago
3 0
Y/x =28/8=3.5
So A is the answer
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Ralph owns a circular farm as shown. He is planning to fence a triangular pigpen ABC in the farm. Point M is the midpoint of the
Flauer [41]

Answer:

Total = \$942

Step-by-step explanation:

Given

A = (0,0)

C = (3,4)

See attachment for farm

Required

The cost of fencing the farm

First, calculate the radius of the farm.

The radius is represented with AC.

So, we have:

AC = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} ---- distance formula

So, we have:

AC = \sqrt{(0 - 3)^2 + (0 - 4)^2}

AC = \sqrt{(- 3)^2 + ( - 4)^2}

AC = \sqrt{9+16}

AC = \sqrt{25}

AC = 5

Hence:

r = 5 --- radius

Calculate the circumference of the circle

C = 2\pi r

C = 2 * 3.14 * 5

C = 31.4yd

If 1 yard costs $30, 31.4 yards will cost:

Total = 31.4 * 30

Total = \$942

5 0
2 years ago
BRAINLIESTTTT ASAP!!!!!!!!!!!!! please answer
Zanzabum
The answer is C. The answer is C.  Mean, because there are no outliers that affect the center

3 0
3 years ago
A. Seven fewer than t
Katyanochek1 [597]

7 fewer than t is:

t - 7

I hope this helps

7 0
3 years ago
Gender: Grade 9 Grade 10 Grade 11 Grade 12
Karolina [17]
There are 31+42+50+61=184 total females, and 50+61=111 females in grades 11 and 12, so the percentage is 111/184*100=60.33 percent, which can be rounded to 60%.
4 0
3 years ago
Read 2 more answers
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
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