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Misha Larkins [42]
3 years ago
13

Please give me the correct answer ​

Mathematics
2 answers:
Marat540 [252]3 years ago
5 0
Last one :) djsjsjdndnwjdjnd
Naily [24]3 years ago
3 0
The Awnser is the last one
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What is the value of k?<br><br> –36 = k – 6
kolezko [41]
Add 6 to both sides
Solution: k = -30
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Ramon wants to make an acute triangle with three pieces of wood. So far, he has cut wood lengths of 7 inches and 3 inches. He st
o-na [289]

Answer: Exactly square root 58 inches

Step-by-step explanation: The dimensions given for the right angled triangle are 7 inches and 3 inches respectively. The third side is yet unknown. However what we know is that a right angled triangle can be solved by using the Pythagoras theorem which states that,

AC^2 = AB^2 + BC^2

Where AC is the longest side. The question requires us to calculate the longest side and with the other two sides already known, the Pythagoras theorem now becomes,

AC^2 = 7^2 + 3^2

AC^2 = 49 + 9

AC^2 = 58

Add the square root sign to both sides of the equation

AC = square root 58 inches

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3 years ago
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How could you use the Distributive Property to rewrite the expression −(8 + 12)?
guajiro [1.7K]

Answer:

-20

Step-by-step explanation:

-8-12=-20

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3 years ago
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The mean for a set of 5 numbers is 24. Four of the numbers 18,30,24, and 27. What is the fifth number?
ioda

Answer:

21 it is the fifth number

5 0
3 years ago
Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected
valina [46]

Answer:

\frac{7}{12}

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

Probability that a black ball is chosen from box B_1 = \frac{1}{2}

Probability that a black ball is chosen from box B_2=\frac{2}{3}

To find:probability that the marble is black

Solution:

Probability that the marble is black = \frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}

6 0
3 years ago
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