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3 years ago

Please give me the correct answer

Mathematics

2 answers:

Marat540 [252]3 years ago

5 0

Last one :) djsjsjdndnwjdjnd

Naily [24]3 years ago

3 0

The Awnser is the last one

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Solve this equation pls

Aleksandr-060686 [28]

Answer:

${ \rm{y = \frac{3 \sqrt{x} + 2x}{ {4x}^{2} } }} \\$

• We are gonna use the quotient rule

${ \boxed{ \bf{ \frac{dy}{dx} = \frac{ {\huge{v} } \frac{du}{dx} - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} } }}} \\$

u is (3√x + 2x)
v is 4x²
du/dx is 3/2√x
dv/dx is 8x

• Therefore:

${ \rm{ \frac{dy}{dx} = \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{(6 {x}^{2})( {x}^{ - \frac{1}{2} } ) - (24 {x}^{ \frac{3}{2} } + 16 {x}^{2} ) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ 6 {x}^{ \frac{3}{2} } - {24x}^{ \frac{3}{2} } - {16x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ - 18 {x}^{ \frac{3}{2} } - 16 {x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\ \\ { \boxed{ \boxed{ \rm{ \: \: \frac{dy}{dx} = - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }} + 9}{8x {}^{ \frac{8}{3} } } \: \: }}}}$

5 0

2 years ago

Read 2 more answers

How do I solve for x?

Marina CMI [18]

Multiply both sides by 2

7 0

2 years ago

Subtract (x² + 5x – 6) – (3x^2 – 7x + 1).<br> What is the difference?

Lorico [155]

1. Distribute the Negative Signs
2. Combine like terms
-2x^2 + 12x-7

4 0

3 years ago

The sum of two numbers is -18. If the first number is 10, which equation represents this situation, and what is the second numbe

ki77a [65]

Don’t know if there’s much of an equation for it, but I guess the best way to write it out is 10 + x = -18. Then, you would subtract the 10 from both sides in order to isolate the x. So then you’re left with x = -28. So -28 is your answer.

8 0

3 years ago

The square root of the quotient of a number n and 3 is equal to the square root of 4 less than the number. Which of the followin

Lisa [10]

Answer:

Step-by-step explanation: You can set up the equation: $\sqrt{\frac{n}{3} }$ = $\sqrt{n-4}$ You square both sides to cancel out the squares which leaves you with $\frac{n}{3}$ = n - 4. Then you just solve as normal which ends you up with an answer of 6. You can check this by plugging 6 back into the equation and see that you end up with $\sqrt{2}$ on both sides.

4 0

2 years ago

Please give me the correct answer ​

Please give me the correct answer