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GaryK [48]
2 years ago
15

100 pts help me please.

Mathematics
1 answer:
Natalija [7]2 years ago
7 0

<u>Answer:</u>

  • Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.

<u>Step-by-step explanation:</u>

We know that:

  • 48 + 8(b) = Carly's expenditure
  • 10(b) = Carly's expenditure
  • 48 + 8b = 10b
  • B = Boxes of cards

<u>Work:</u>

  • 48 + 8b = 10b
  • => 48 + 8b - 8b = 10b - 8b
  • => 48 = 2b
  • => b = 24

<u>Now, let's substitute the value of b into any equation.</u>

  • 10(24)
  • => 240

<u>Hence, Carly's expenditure was $240 and the number of boxes of cards was required is 24 boxes.</u>

Hoped this helped.

BrainiacUser1357

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Triangle ABC is an isosceles right triangle inscribed in a circle. The center of the circle is point D and the diameter of the c
Paha777 [63]

Answer:

* AD is congruent to DC and BD <em>true</em>

* m∠B = 90° <em>true</em>

<u>* The measure of arc AC is equal to the measure of arc AB </u><u><em>not be true</em></u><em> ( The right answer  )</em>

* The measure of arc AB is equal to measure of arc BC <em>true</em>

Step-by-step explanation:

∵ D is the center of the circle and A , B and C are points on the circle

∴ AD , DB and DC are radii on the circle D

∴ AD ≡ DC ≡ DB

∵ AC passing through point D which is the center of the circle

∴ AC is the diameter of the circle D

∵ ∠B is opposite to the diameter of the circle and vertex B lies on the circle

∵ ∠B is an inscribed angle and  ∠ADC  is a central angle subtended by the same arc AC

∴m∠B = half m∠ADC

∵ m∠ADC = 180°

∴ m∠B = 90°

∵ The measure of arc AC = 180°

∵ ΔABC is isosceles and m∠B = 90°

∴ m∠BAC = m∠BCA = (180° - 90°) ÷ 2 = 45°

∵ ∠ACB is an inscribed angle subtended by arc AB

∴ m∠ACB = half measure of arc AB

∵ The measure of arc AB = 45° × 2 = 90°

∴ The measure of arc AC ≠ the measure of arc AB

∵ Δ ABC is an isosceles triangle and m∠B = 90°

∴ AB = BC

∵ AB subtended by arc AB

∵ BC subtended by arc BC

∴ The length of arc AB = the length of arc BC

∵ If two arcs are equal in length, then they will be equal in measure

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3 0
3 years ago
The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =
Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year                                          

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

                                   L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year  can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

                             dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

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                            L'(t) = 34.416*e^(-0.18*t)

                            L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

                            L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

                            L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

- Next, again use the derived L'(t) to determine the year when fish is growing at a rate of 6 cm/yr:

                             6 cm/yr = 34.416*e^(-0.18*t)

                             e^(0.18*t) = 34.416 / 6

                             0.18*t = Ln(34.416/6)

                             t = Ln(34.416/6) / 0.18

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Answer:

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Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

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We have <em>m = 0, (3, 1) → x₁ = 3, y₁ = 1</em>.

Substitute:

y-1=0(x-3)

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Other method.

If the slope is equal 0, then it's a horizontal line.

The equation of a horizontal line: <em>y = a</em>.

We have the point on a line (3, 1) → x = 3, y = 1.

Therefore the equation is <em>y = 1</em>.

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