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Margarita [4]
3 years ago
7

The ages of Edna, Ellie, and Elsa are consecutive integers. The sum of their ages is 123. What are their ages? Show work.

Mathematics
2 answers:
Lynna [10]3 years ago
8 0

Answer:

Ellie's age is 41, Edna's age is 40, Elsa's age is 42

Step-by-step explanation:

Let Ellie's age be x. Because they're consecutive integers, Edna's age is x-1 and Elsa's age is x+1. Therefore, 3x=123, x=41, so Ellie's age is 41, Edna's age is 40, Elsa's age is 42

Sonbull [250]3 years ago
8 0

Answer:

Edna is 40, Ellie is 41 and Elsa is 42.

Step-by-step explanation:

let Edna be m years old

m - Edna

m+1 - Ellie

m+2 - Elsa

m+m+1+m+2=123

Collect like terms

3m+3=123

3m=123-3

3m=120

Divide through by 3

m=40

Therefore, Edna is m=40 years old

Ellie=m+1=41 years old

Elsa=m+2=42 years old.

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The revenue is given by the unit price * number of units.
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For profit to be maximum dP/dx = 0
120 - 0.006x = 0
x = 120/0.006 = 20,000

Therefore, to maximize profit, the firm should produce 20,000 penicillin.
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What is the solution to log 2 (2x^3 -8 )-2log 2 x=log 2x
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x=9

Step-by-step explanation:

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From 1960 to 1980 the consumer price index increased from 29.6 282.4 if a pound of grapes cost $.14 in 1960 and the price of gra
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4 years ago
Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Masteriza [31]
Part A)

f(x) = 5^x
f(0) = 5^0
f(0) = 1
----------
f(x) = 5^x
f(1) = 5^1
f(1) = 5
----------
f(x) = 5^x
f(2) = 5^2
f(2) = 5*5
f(2) = 25
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f(x) = 5^x
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f(3) = 5*5*5
f(3) = 125

-------------------

Rate of change for section A = (f(1) - f(0))/(1 - 0)
Rate of change for section A = (5 - 1)/(1 - 0)
Rate of change for section A = 4/1
Rate of change for section A = 4

Rate of change for section B = (f(3) - f(2))/(3 - 2)
Rate of change for section B = (125 - 25)/(3 - 2)
Rate of change for section B = 100/1
Rate of change for section B = 100

================================================

Part B)

From part A) above, we found,

Rate of change for section A = 4
Rate of change for section B = 100

Which means that section B's rate of change is 25 times greater (since 100/4 = 25, or 25*4 = 100)

Answer for part B: 25

================================================

Extra:  Explain why one rate of change is greater than the other.

The rate of change for section B is larger because the exponential function is growing faster as x increases. This is shown visually by the sharper and steeper incline as the function curve goes upward. The function starts off with relatively slower growth but it accelerates in speed. 

6 0
3 years ago
1) 3 (x - y)² - 10 (x-y) + 8​
katovenus [111]

Answer:

(3x-3y-4)(x-y-2)

Step-by-step explanation:

Given expression:

3(x-y)^2-10(x-y)+8

Let u = (x - y):

\implies 3u^2-10u+8

To factor a quadratic in the form  ax^2+bx+c  find two numbers that multiply to ac and sum to b:

\implies ac=3 \cdot 8=24

\implies b=-10

Therefore, the numbers are: -6 and -4.

Rewrite b as the sum of these two numbers:

\implies 3u^2-6u-4u+8

Factor the first two terms and the last two terms separately:

\implies 3u(u-2)-4(u-2)

Factor out the common term (u - 2):

\implies (3u-4)(u-2)

Substitute back in u = (x - y):

\implies (3(x-y)-4)((x-y)-2)

Simplify:

\implies (3x-3y-4)(x-y-2)

3 0
2 years ago
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