Answer:
q = mC∆T
q = (50 g)(4.184 J/g/deg)(10 deg)
q = 2092 J = 2.09x10^3 J
That's how it's done.
Explanation:
Hope this helps! sorry If i didn't simplify enough..
Answer:
80°C
Explanation:
because I'm mixed temperature of watere
Answer:
0.482 ×10²³ molecules
Explanation:
Given data:
Volume of gas = 2.5 L
Temperature of gas = 50°C (50+273 = 323 k)
Pressure of gas = 650 mmHg (650/760 =0.86 atm)
Molecules of N₂= ?
Solution:
PV= nRT
n = PV/RT
n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k
n = 2.15 atm. L /26.52 atm. mol⁻¹.L
n = 0.08 mol
Number of moles of N₂ are 0.08 mol.
Number of molecules:
one mole = 6.022 ×10²³ molecules
0.08×6.022 ×10²³ = 0.482 ×10²³ molecules
Answer:
9,500J
Explanation:
Distance= 50m
Force = 190N
Energy = Force x distance
= 190 x 50
= 9,500J
Answer:
67.5 atm
Explanation:
To answer this problem we can use <em>Boyle's law</em>, which states that at constant temperature the pressure and volume of a gas can be described as:
P₁V₁=P₂V₂
In this case:
P₁ = 101.3 atm
V₁ = 0.500 L
P₂ = ?
V₂ = 0.750 L
We input the data:
101.3 atm * 0.500 L = P₂ * 0.750 L
And solve for P₂:
P₂ = 67.5 atm