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Leni [432]
2 years ago
5

Is this statement true or false? Ammonia is a base. true false

Chemistry
1 answer:
Vanyuwa [196]2 years ago
3 0

Answer: ------------------------------------------------------------------------------------------------------------------------

Explanation: True, Ammonia is a base

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A sample of silver has a mass of 21 grams
ad-work [718]

Answer:

density \: of \: the \: silver =  \frac{mass}{volume}  =  \frac{21}{2} \\   = 10.5 \: gram {(cm)}^{ - 3}

<h2>10.5 gram(cm)^-3 is the right answer.</h2>

8 0
3 years ago
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a seismic station in gainesville florida recorded the arrival of the first p wave at 1:30:00 and the first s wave from the same
kvasek [131]

Answer:

4 hours and 30 minutes

Explanation: because first wave was 1:30:00 and the second is 1:34:30

1:30:00 goes into 1:34:30 4 hours and 30 minutes.

6 0
2 years ago
How many moles of MgCO3 are in 2.57g of MgCO3?
Sveta_85 [38]

Answer:

0.0305 moles of MgCO₃

Explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

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  • MgCO₃ MW = 24.3 + 12 + 16*3 = 84.3 g/mol

Finally we <u>divide the mass by the molecular weight</u>, to calculate the <em>number of moles</em>:

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7 0
3 years ago
A star produces energy by:
frosja888 [35]

Answer : C

Explanation:

a star produces energy by combining two atoms into one creates a powerful burst of energy

3 0
3 years ago
For the following, identify the most likely value for x.a. BHx b. CHx c. NHx d. CH2Clx
vekshin1

Given :

a. BH_x b. CH_x c. NH_x d. CH_2Cl_x .

To Find :

Find the most likely vale of x for each one .

Solution :

a . BH_x

Because boron have valency of 3 .

So , x = 3 .

b . CH_x

Valency of carbon is 4 .

x = 4 .

c . NH_x

Valency of nitrogen is 3 .

Therefore , x = 3 .

d . CH_2Cl_x

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .

5 0
4 years ago
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