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Pachacha [2.7K]
2 years ago
10

Tell whether the ordered pair is a solution to the system.

Mathematics
2 answers:
DerKrebs [107]2 years ago
7 0

Answer:

no

Step-by-step explanation:

no. substitute -1 for x and -2 for y.

the first one is -1 - 10

this equals -11 not 3

Pavlova-9 [17]2 years ago
6 0
I think it’s a no but but I’m not sure
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Which relation is a function?
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2 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
You want to deliver a package to japan.the fed ex delivery service charges a $15 flat fee plus $2 per additional kilogram. You c
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7 0
3 years ago
Need the (x) & (y) value
Katen [24]

Answer:

x=0

y=6

Step-by-step explanation:

Two equations with two unknowns can be solved. Use the three steps given below.

In general you can save time if you use the simplest expression for step 1. You can choose either expression to start with x =.. or you can rewrite it, so it starts with y =...

FOLLOW THESE STEPS:

1. Rewrite the first expression so it starts with y =...

2. Then use that expression and substitute it in the other expression, to find the value for x.

3. Use that value found in step 2. and substitute it in the rewritten expssion you created in step 1. Solve this last expression and you'll get the value for y.

Step 1.

-6y + 11x = -36

-6y = -11x -36

multiply left and right of the = sign by -1

6y = 11x + 36

divide left and right of the = sign by 6

y = 11x/6 + 36/6

y = 11/6x + 6

Step 2.

-4 * ( y ) + 7x = -24

-4 * ( 11/6x + 6 ) + 7x = -24

( -44/6x - 24 ) + 7x = -24

-44/6x + 7x = -24 + 24

You can see immediately that ...x = 0

Just for fun of it ....

-44/6x + 42/6x = 24 - 24

(-44+42)/6x = 0

-2/6x = 0

-1/3x = 0

multiply left and right of the = sign by -3

3/3x = 0 * -3

x = 0

Step 3.

y = 11/6( x ) + 6. and substitute x = 0 gives:

y = 11/6( 0) + 6

y = 0 + 6

y = 6

3 0
3 years ago
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