Answer:
The width and length of rectangle is 12.728 m
Step-by-step explanation:
Let the length of the rectangle = L
let the width of the rectangle = W
The subjective function is given by;
F(p) = 2(L + W)
F = 2L + 2W
Area of the rectangle is given by;
A = LW
LW = 162 ft²
L = 162 / W
Substitute in the value of L into subjective function;
Take the second derivative of the function, to check if it will given a minimum perimeter
Determine the critical points of the first derivative;
df/dw = 0
L = 162 / 12.728
L = 12.728 m
Therefore, the width and length of rectangle is 12.728 m
Take the first bracket and it's multiplication, 3(2a+5)
You expand my multiplying everything inside the bracket by the number outside.
3*2a = 6a
3*5 = 15
Then multiply out the second bracket, 5(a-2)
5*a = 5a
5*-2 = -10
So now you have 6a + 15 + 5a - 10
Simplify it by collecting like terms, and you have:
11a + 5
And that's the answer, hope I helped!
Let's rewrite the binomial as:
Using the binomial expansion, we get:
For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.
Thus, the fifteenth term is:
I'm pretty sure this is right because there is 1.5 per one Wich is also written as a fraction
Just subtract 27 from 31.25
31.25-27=4.25
Brandon must cut 4.25 seconds
