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Vinil7 [7]
3 years ago
13

Joe and Maxine are playing a game where they flip a fair coin four times and try to predict the outcomes. Joe thinks that the pr

obability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips. Maxine disagrees. She thinks that the two probabilities are equal.
Mathematics
2 answers:
timofeeve [1]3 years ago
8 0

Answer: Joe is right, the probability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips.

Step-by-step explanation:

First creating a sample space :

HHHH, HHHT, TTHT, HTTH, THHH, TTTT, TTTH, TTHH, HTHH, HTTT, HHTT, THTH, HHTH, THTT, HTHT, THHT

A fair coin (H - HEAD, T - TAIL)

Probability = (required outcome / possible outcome)

Probability getting exactly two heads in first four flips:

= 6/16 = 3/8

Probability of getting head on both the first and second flips :

= 4/16 = 1/4

Therefore Joe is right, the probability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips.

Nezavi [6.7K]3 years ago
6 0

Answer:

Maxine is correct.

Step-by-step explanation:

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From the set (76, 77, 78), use substitution to determine which value of x makes the equation true
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Step-by-step explanation:

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Hope this helps!

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What is the solution to q/-7=6?
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Answer:

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sammy [17]
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The equation for point-slope form is: y-y1 = m (x-x1)

Let's plug in the points into the equation. 
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