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CaHeK987 [17]
2 years ago
5

What is the value of the expression 5 + 6 x (5 - 2) + 9

Mathematics
1 answer:
s2008m [1.1K]2 years ago
8 0
I believe its 18x + 14
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What is the absolute value of the distance from the numbers -6 to 5?
katovenus [111]

Answer: 11

Step-by-step explanation:

It is 11 because count from -6...

-6 = 0

-5 = 1

-4 = 2

-3 = 3

-2 = 4

-1 = 5

0 = 6

1 = 7

2 = 8

3 = 9

4 = 10

5 = 11

Hope this helpsand sorry if not

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3 years ago
What is 24 1/4 % expressed as fraction?
VashaNatasha [74]

Answer:

97/4

Step-by-step explanation:

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Select all that apply to describe the association of this scatterplot
raketka [301]
Negative, Nonlinear,
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3 years ago
Im confused and i need help please help
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Answer:

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Step-by-step explanation:

8 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
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