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3 years ago

Move the numbers to the blanks to order them from least to greatest value.

Mathematics

2 answers:

Naddika [18.5K]3 years ago

7 0

Answer:

1-21, -0.89, 1/2, 0.4, 9/8

Step-by-step explanation:

IrinaK [193]3 years ago

5 0

Answer: -0.89 1-21 0.4 1/2 9/8

Step-by-step explanation:

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Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel.

DochEvi [55]

X is Kevin; Y is Dan

X = 3Y

X - 4 = 5(Y - 4)

3Y - 4 = 5(Y - 4)
3Y - 4 = 5Y - 20
   + 4 +4
4 cancels each other out.
3Y = 5Y - 16
   - 5 -5
5 cancels each other out.
-2Y = -16
/2 /2
   Y = 8

X = 3Y;
X = 3 x 8;

Thus,
X = 24;
Kevin(x) is 24

8 0

3 years ago

Estimate the line of best fit using two points on the line (20,62)(10,32)

Olegator [25]

Answer: y = 3x+2

Step-by-step explanation:

slope = (62-32)/(20-10)

point-slope form -> y - 32 = 3(x -10)

y = 3x+2

8 0

3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

3 years ago

2. Zariya received a discount of 11% on a dress costing $85.50. How much did she pay for the dress?

erastova [34]

Answer:D

Step-by-step explanation:

5 0

2 years ago

PLEASE HELP IM STUCK ON THIS

Ronch [10]

Pick 2 coordinates:

I choose first & last one (0,15) & (8-9)

Change in y is 24

(15--9 = 24)

Change in x is 8

(0 - 8) = - 8

24/-8 = - 3

So, slope = - 3

Hope this helps!

8 0

2 years ago

Read 2 more answers