Ask question

Ask question

All categories

3 years ago

10

A new car is purchased for 17300 dollars. The value of the car depreciates at 9.25% per year. What will the value of the car be,

, after 15 years?

1 answer:

ladessa [460]3 years ago

4 0

Answer:

There is a answer to the question

You might be interested in

Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu

Lesechka [4]

Answer:

Approximately $4.75$ .

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of $\rm CH_3COOH$ and $\rm CH_3COO^{-}$ are equal.

${\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}$

Since $\rm CH_3COONa$ is a salt soluble in water. Once in water, it would readily ionize to give $\rm CH_3COO^{-}$ and $\rm Na^{+}$ ions.

Assume that the $\rm CH_3COOH$ and $\rm CH_3COO^{-}$ ions in this solution did not disintegrate at all. The solution would contain:

$0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol$ of $\rm CH_3COOH$ , and

$0.06\; \rm mol$ of $\rm CH_3COO^{-}$ from $0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol$ of $\rm CH_3COONa$ .

Accordingly, the concentration of $\rm CH_3COOH$ and $\rm CH_3COO^{-}$ would be:

$\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}$ .

$\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}$ .

In other words, in this buffer solution, the initial concentration of the weak acid $\rm CH_3COOH$ is the same as that of its conjugate base, $\rm CH_3COO^{-}$ .

Hence, once in equilibrium, the $\rm pH$ of this buffer solution would be the same as the ${\rm pK}_{a}$ of $\rm CH_3COOH$ .

Calculate the ${\rm pK}_{a}$ of $\rm CH_3COOH$ from its ${\rm K}_{a}$ :

$\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}$ .

7 0

3 years ago

Are you good in math?

Karo-lina-s [1.5K]

Not really, is this a rhetorical question? lol

3 0

4 years ago

The snack bar at your school has added sushi to its menu. The ingredients for one roll include sushi rice, seaweed sheets, cuc

amid [387]

Answer:

The answer si:

- 16 servings - 6 oz of salmon

- 24 servings - 9 oz of salmon

- 80 servings - 30 oz of salmon

- 100 servings - 37.5 oz of salmon

1 roll is 8 servings and it is also made of 3oz of smoked salmon. That means that 3oz of smoked salmon is needed fo 8 servings.

Now, let's made some proportions:

16 servings:

3 oz is for 8 servings, how much oz is for 16 servings:

3 : 8 = x : 16

x = 3 · 16 ÷ 8 = 6 oz

24 servings:

3 oz is for 8 servings, how much oz is for 24 servings:

3 : 8 = x : 24

x = 3 · 24 ÷ 8 = 9 oz

80 servings:

3 oz is for 8 servings, how much oz is for 80 servings:

3 : 8 = x : 80

x = 3 · 80 ÷ 8 = 30 oz

100 servings:

3 oz is for 8 servings, how much oz is for 100 servings:

3 : 8 = x : 100

x = 3 · 100 ÷ 8 = 37.5 oz

5 0

3 years ago

Austin and Dale earn money by painting fences over the summer. Working alone, Austin takes 3 hours longer than Dale to paint a f

mojhsa [17]

Answer:

Austin will take 9 hours to paint a room and dale with take 3 hours to paint a room

Step-by-step explanation:

3 0

3 years ago

Solve for x. Show the equation you used and your work.

IgorC [24]

Here, You need to apply "Proportionality Theorem"
According to this theorem, the ratio of components of a leg would be equal to the ratio of corresponding components of another leg.

In mathematical form,
TV/VS = TW/WU

Substitute their values,
14/6 = 21/(x+4)
14(x+4) = 21*6
14x+56 = 126
14x = 126-56
x = 70/14
x = 5

In short, Your Answer would be 5

Hope this helps!

4 0

3 years ago