All categories

1 year ago

What is the equation of the line passing through the points (-3,7) and (3,3)

2 answers:

6 0

$\text{Given that,}\\\\(x_1,y_1) = (-3,7)~~ \text{and}~~(x_2,y_2) =(3,3)\\\\\\\text{Slope, }~~ m =\dfrac{y_2-y_1}{x_2 - x_1}= \dfrac{3-7}{3-(-3)} = -\dfrac{4}{3+3} = -\dfrac 46 = -\dfrac 23\\\\\\\text{Equation with given points ,}\\\\y- y_1 = m(x-x_1)\\\\\implies y -7 = -\dfrac 23 (x +3)\\\\\implies y -7= -\dfrac 23 x - 2\\\\\implies y = -\dfrac 23 x -2 +7 \\\\\implies y = -\dfrac 23 x +5\\\\\implies 3y = -2x +15 \\\\\implies 2x +3y = 15$

abruzzese [7]1 year ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$

5 0

2 years ago

Read 2 more answers

For what value of k will the relation y = kx² + 8x + 8 have only one zero? (3 marks)

Lana71 [14]

Answer:

Step-by-step explanation:

2x^2 + 8x + 8

factor the 2 out : 2(x^2 + 4x + 4)

2(x + 2)^2

x = -2

4 0

2 years ago

this is part 2 and you just have to find the total area in sq ft and also answer how much material do you need to make 3 backpac

Lubov Fominskaja [6]

1. 1 1/8= 18/16

5/16*2= 10/16

4/16*2= 8/16

9/16= 9/16

1/2= 8/16

18/16 + 10/16 + 8/16 + 9/16 + 8/16= 53/16

Simplify:

4 & 5/16sq ft

2. All you do is multiply that by 3... so 4 & 5/16 = 53/16 53/16*3 = 159/16 = 9 & 15/16 sq ft

8 0

2 years ago

What is (2x+1) (3x+2)?

Pie

Answer:

In picture...

Step-by-step explanation:

I solved it step by step in picture. U can have a look

✌️

7 0

2 years ago

Read 2 more answers

Pleasssssssseeee help

astra-53 [7]

Rates like $ per channel is a slope, "m". The added fee is a constant so it's the intercept "b".
y = mx + b

So for the first problem (9)
(a)
y = total cost in dollars
x = number of premium channels
y = 16x + 44
(b) when x = 3 channels
y = 16(3) + 44
y = 92 $

the second problem (10)
(a) every 4 years the tree grows by 12-9=3 ft
So the unit rate or slope will be 3 ft per 4 yrs, (3/4). You can see this also by solving for slope "m" using the given points (4,9) and (8,12).

x = number of years
y = height of tree in ft
y = (3/4)x + b
use one of the points to find the y-intercept "b".

9 = (3/4)(4) + b
9 = 3 + b
9 - 3 = b
6 = b
y = (3/4)x + 6

(b) when x = 16
y = (3/4)(16) + 6
y = 12 + 6
y = 18 ft

5 0

2 years ago