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nikitadnepr [17]
3 years ago
13

PLZ PLZ PLZ HELP

Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

f (2/5 ) = −2/3*2/5  + 5

Which is -4/15+5

Which is 71/15

But it is not one of the multiple choices please update when you figure out where you copied incorrectly

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<img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B8x%20%2B%2012%20%2B%204%20%3D%2010%7D%20" id="TexFormula1" title=" \sqrt{8x +
tiny-mole [99]

Answer:

x=3

Step-by-step explanation:

I am assuming that your equation is:

\sqrt{8x + 12}  + 4 = 10

Subtract 4 from both sides to get:

\sqrt{8x + 12}  = 6

Square both sides to get:

(\sqrt{8x + 12})^{2}  =  {6}^{2}

8x + 12 =3 6

8x =24

Divide both sides by 8 to get:

x =  \frac{24}{8}  = 3

6 0
4 years ago
Find a closed-form solution to the integral equation y(x) = 3 + Z x e dt ty(t) , x &gt; 0. In other words, express y(x) as a fun
MrMuchimi

Answer:

y{x} = \sqrt{7+2Inx}

Step-by-step explanation:

y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}

Let say; By y(x)= y(e)  

we have;  

y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

y^{1} (x) = 0 + 1/ xy

y^{1} = 1/xy  

dy/dx = 1/xy  

\int\limits {y} \, dxy = \int\limits \, dx/x

y^{2}/2 Inx + C

RECALL: y(e) = 3  

(3)^{2} / 2 = In (e) + C  

\frac{9}{2} =In(e)+C  

\frac{9}{2} - 1 = C

\frac{7}{2} = C  

y^{2} / 2 = In x +C

y^{2} / 2 = In x +7/2

MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

y^{2} = {7+2Inx}  

y{x} = \sqrt{7+2Inx}

8 0
3 years ago
Solve: 5 + n &gt; 2
tiny-mole [99]

\\ \sf\longmapsto 5+n>2

  • We have to find n
  • Take 5 to right side
  • sign will be changed

\\ \sf\longmapsto  n>2-5

  • Simplify

\\ \sf\longmapsto n>-3

3 0
3 years ago
How do you grow your own equations
natita [175]
You can formulate your own equations by analyzing the given problem and its statements. You can do some illustrations so you can understand it better. Introduce some variables and the rest is algebra. For example:

An orange costs $2 while a banana costs $1.5. How many oranges and bananas do you have to buy such that the total cost would equal to $20. You bought a total of 12 fruits.

First, you have to introduce variables. Let 'x' be the number of oranges and 'y' be the number of bananas. One equation you can get from here is knowing the amount of total cost: 2x + 1.5y = 20. Then, the other equation would be knowing the amount of fruits: x+y=12. You have two unknowns and two equations. Hence, you can solve the problem. Solving them simultaneously, you would get that x=4 and y=8.
4 0
4 years ago
For each question, calculate the slope of a line that passes through the points
LekaFEV [45]
I don’t know it’s hard tho
8 0
3 years ago
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