We know that
if cos x is positive
and
sin x is negative
so
the angle x belong to the IV quadrant
cos x=5/13
we know that
sin²x+cos²x=1-------> sin²x=1-cos²x------> 1-(5/13)²---> 144/169
sin x=√(144/169)-------> sin x=12/13
but remember that x is on the IV quadrant
so
sin x=-12/13
Part A) <span>cos (x/2)
cos (x/2)=(+/-)</span>√[(1+cos x)/2]
cos (x/2)=(+/-)√[(1+5/13)/2]
cos (x/2)=(+/-)√[(18/13)/2]
cos (x/2)=(+/-)√[36/13]
cos (x/2)=(+/-)6/√13-------> cos (x/2)=(+/-)6√13/13
the angle (x/2) belong to the II quadrant
so
cos (x/2)=-6√√13/13
the answer Part A) is
cos (x/2)=-6√√13/13
Part B) sin (2x)
sin (2x)=2*sin x* cos x------> 2*[-12/13]*[5/13]----> -120/169
the answer Part B) is
sin(2x)=-120/169
The answer is x = 6.
Here are the steps.
1. Simplify 2/6 to 1/3 ( 2/x = 1/3 ).
2. Multiply both sides by x ( 2 = 1/3x ).
3. Simplify 1/3x to x/3 ( 2 = x/3 ).
4. Multiply both sides by 3 ( 2 * 3 = x ).
5. Simplify 2 * 3 to 6 ( 6 = x ).
Now finally switch it up and the answer is x = 6.
Answer:
The scale factor of the dilation is 1/5
Step-by-step explanation:
bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.
now, they both intersect at 0,0, namely they both pass through it, we know the slope of the first one, so
so, we're really looking for the equation of a line whose slope is 2, and runs through (0,0).
The original price I believe is $2.60
