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Yakvenalex [24]
3 years ago
10

Please help me!!! Click the image to see the question I need help

Mathematics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

it on the paper

Step-by-step explanation:

You might be interested in
Help please and thank you
gulaghasi [49]

Answer:

56

Step-by-step explanation:

Missing length = x + 21

Based on the Three Parallel Lines Theorem, we have:

x/21 = 20/12

Cross multiply

x*12 = 20*21

12x = 420

12x/12 = 420/12

x = 35

✅Missing length = x + 21

Plug in the value of x

= 35 + 21

= 56

3 0
3 years ago
What is the difference of two numbers is 90 and their quotient is 10
katrin2010 [14]
This should be your answer I guess.

7 0
4 years ago
Need help with I ready math
vovangra [49]

Answer:

5(P - 1.00) + 3(P - 0.75)

Step-by-step explanation:

Cost of a package in store A = $P

Discount offered at store A = $1.00

Price paid per package at store A = Cost of a package in store A - Discount offered at store A

= P - 1.00

Cost of a package in store B = $P

Discount offered at store B = $0.75

Price paid per package at store B = Cost of a package in store B - Discount offered at store B

= P - 0.75

Total cost of 5 packages at store A and 3 packages at store B = 5(P - 1.00) + 3(P - 0.75)

4 0
3 years ago
What is the sum of the first 30 terms of the arithmetic series 27,32,37,42,47
AlladinOne [14]

Answer:

2985

Step-by-step explanation:

The formula for the sum of an arithmetic series is given by the formula:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the first term, and x_k is the last term. In this case, the last term is the 30th term because we are finding the sum of the first 30 terms.

So, we need to find the 30th term. To do so, we can write an explicit formula for our sequence.

The standard form for an arithmetic sequence is given by the formula:

x_n=a+d(n-1)

Where a is the initial term and d is the common difference.

From our sequence, we can see that the initial term a is 27. The common difference is 5 because each term is 5 greater than the previous one.

So, our equation is:

x_n=27+5(n-1)

So, to find the 30th term, substitute 30 for n:

x_{30}=27+5(30-1)

Subtract:

x_{30}=27+5(29)

Multiply:

x_{30}=27+145

Add:

x_{30}=172

So, the 30th term is 172.

Now, substitute this into our original sum formula:

S=\frac{k}{2}(a+x_k)

Substitute 30 for k (the amount of terms), 27 for a (the first term), and 172 for x_k (the 30th and last term). So:

S=\frac{30}{2}(27+172)

Reduce and add:

S=15(199)

Multiply:

S=2985

So, the sum of the first 30 terms is 2985.

3 0
3 years ago
A moving company charges a 75$ flat rate plus and additional $0.19 per mile driven. Which inequality correctly represents how fa
lidiya [134]
Your answer is choice (D), total equals $100.08: so you would want X to equal equal or greater than 132
4 0
3 years ago
Read 2 more answers
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