Answer:
In a homozygous state, the allele "P" is lethal. Those individuals with PP genotype will be born dead.
Explanation:
The allele P is dominant over p and expresses the trait "platinum". But in the homozygous state, it is mortal, PP. The allele p expresses the "Silver" trait.
This is:
- For platinum individuals, the genotype should be Pp
- For silver individuals, the genotype should be pp
- For dead individuals, the genotype should be PP.
So in the crosses, the punnet squares are:
1- Silver x Silver
Parental) pp x pp
Gametes) p p p p
Punnet square)
p p
p pp pp
p pp pp
F1 Genotype) 100 % recessive homozygote pp
2- Silver x Platinum
Parental) pp x Pp
Gametes) p p P p
Punnet square)
p p
P Pp Pp
p pp pp
F1 Genotype) 50 % recessive homozygote pp,
50% heterozygote for the trait Pp
3- Platinum x Platinum
Parental) Pp x Pp
Gametes) P p P p
Punnet square)
P p
P PP Pp
p Pp pp
F1 Genotype) 25 % recessive homozygote pp
50% heterozygote for the trait Pp
25% dominant homozygote PP. This is a dead
individual.
In this last cross, individuals with genotype PP dye, so, of the whole offspring, there are two platinum for each silver offspring.
Group 5 contains vanadium (V), niobium (Nb), tantalum (Ta) and dubnium (Db). This group lies in the d-block of the periodic table. The group itself has not acquired a trivial name; it belongs to the broader grouping of the transition metals.
This is because a sample is supposed to ideally represent the whole population from which it was taken. Taking samples from different location within the population ensures that they are no bias in the sample. Each part of the population should be well represented in the sample so that the conclusions drawn from the sample represent the properties of the whole population.
The answer is Optic Chiasma
