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MakcuM [25]
2 years ago
5

In sentence 6 (reproduced below), the writer is considering deleting the underlined text. However, strong evidence indicates tha

t this event did not inspire the poem and that the author was in fact sarah josepha hale, not roulstone. Should the writer keep or delete the underlined text?.
SAT
1 answer:
Korvikt [17]2 years ago
5 0

Based on the information given, the correct option will be C. Keep it, because it previews the way the rest of the passage will support the thesis about Hale's authorship with evidence.

From the question, it was stated that one should show what the author should do with the underlined text.

The underlined text is important as it gives a preview of the passage. It's also used as supporting evidence to the claim of Hale.

Learn more about texts on:

brainly.com/question/20266552

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A car averages 22 miles per gallon. If gas costs $2.89 per gallon, which of the following is closest to how much the gas would c
Alja [10]
You take 1,650/22=75
Then 75•2.89
So your answer is $216.75 is how much it would cost to go 1,650 miles
4 0
3 years ago
If a person takes 30 ml of vinegar a day and the molarity of the vinegar is 0. 84 m then how many grams of acetic acid (hc2h3o2
babunello [35]

The mass of the acetic acid is 1.512 g.

<h3 /><h3>What is Molarity?</h3>

molarity is the concentration of a substance in mol per dm³

From the question,

The number of moles contained in the 30 mL vinegar is

  • n = (0.84×30)/1000
  • n = 0.0252 mol.

the molar mass of vinegar is calculated below.

  • m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
  • m.m = (1+24+3+32]
  • m.m = 60 g/mol.

To calculate the mass of acetic acid, we use the formula below.

  • R.m = n×m.m............. Equation 1

Where

  • R.m = mass of acetic acid.

Substitute these values into equation 1

  • R.m = (0.0252×60)
  • R.m = 1.512 g.

Hence, The mass of the acetic acid is 1.512 g.

Learn more about molarity here: brainly.com/question/20383725

8 0
3 years ago
Dr. Peters has been so busy managing erratic blood sugars and chronic knee pain in one of his patients, that he didn't realize s
kogti [31]

With the help of pop-up notifications (alerts) within the EHR, Dr. Peters is given reminders for specific screening tests for patients.

<h3>What is EHR?</h3>

EHR is an acronym for electronic health record and it can be defined as a systematized collection of a patient's medical history that are electronically stored in a digital format.

In this context, we can infer and logically deduce that with the help of pop-up notifications (alerts) within the electronic health record (EHR), Dr. Peters is given reminders for specific screening tests for patients.

Read more on electronic health record here: brainly.com/question/7423076

#SPJ1

6 0
2 years ago
Which of the following minerals is beneficial to plants? a. Nitrogen c. Aluminum b. Mercury d. Limestone
Vikentia [17]
I would select A. Nitrogen due to the fact Nitrogen is found in most soil samples and Aluminum and mercury are metals. Also, limestone i don't find beneficial to plants whatsoever.
3 0
3 years ago
Read 2 more answers
company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul
lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

  • <em>The proportion of Good TV set is 0.67</em>
  • <em>The number of ways of selecting 5 from 6 TV sets is 6</em>
  • <em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

n = 6

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

Good = 4

So, the proportion (p) that are good are:

p = \frac{Good}{n}

p = \frac{4}{6}

p = 0.67

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 5

So, we have:

^6C_5 = \frac{6!}{(6 - 5)!5!}

^6C_5 = \frac{6!}{1!5!}

^6C_5 = \frac{6 \times 5!}{1 \times 5!}

^6C_5 = \frac{6}{1}

^6C_5 = 6

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 4

So, we have:

^6C_4 = \frac{6!}{(6 - 4)!4!}

^6C_4 = \frac{6!}{2!4!}

^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}

^6C_4 = \frac{30}{2}

^6C_4 = 15

So, the table is as follows:

\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

p = \frac{Good}{n}

<u>(d) The sampling distribution</u>

In (a), we have:

p = 0.67 --- proportion of Good TV

The sampling error is calculated as follows:

SE_n = |p - p_n|

So, we have:

\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]

Read more about sampling distributions at:

brainly.com/question/10554762

3 0
3 years ago
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