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docker41 [41]
3 years ago
12

(I just need help on b)

Mathematics
1 answer:
ddd [48]3 years ago
4 0
B.) Do you notice clusters or outliers in the data? Explain your reasoning.(2 points) The answer is 3100
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Line AB is Perpendicular to line BC. A=(-3,2) and C=(2,7). Which of the following could be the coordinates of B? Select all that
Llana [10]

Answer:

The answer would be Choice F; (-3,7)

Step-by-step explanation:

  1. Plot the two guaranteed given points
  2. A, (-3,2) and C, (2,7)
  3. Find the point where the x and y would share and then form a right angle. This is called being Perpendicular.
  4. So, take the <em>x</em> of A, and the <em>y</em> of C and you have the coordinates of B.

(-3,7)

6 0
3 years ago
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Please help I appreciate it
Anni [7]

Answer:

A

Step-by-step explanation:

g(x) got smaller

A - makes it thinner

B & C - move it to the left or right

D- makes it wider

4 0
3 years ago
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What percent of increase for a population that changed from 25,000 to 30,000
tiny-mole [99]

percent of increase for a population that changed from 25,000 to 30,000

Increase in population = 30,000 - 25,000 = 5000

So, the increase in population is 5000

To find percent of increase , we divide the increase in population by initial population.

So percent of increase = \frac{5000}{25000} * 100

= 0.2 * 100

= 20 %

20% of increase for a population that changed from 25,000 to 30,000.

7 0
3 years ago
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Please helppp answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!
horrorfan [7]

Answer:

21

Step-by-step explanation:

Remember that the centroid splits the 3 medians of a triangle into a ratio of 1:2

Since TS < TN, TS = 42/2 = 21

7 0
2 years ago
How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen
VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

4 0
3 years ago
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