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2 years ago

The endpoints of cd are c(3,-5) and D(7,9). The coordinates of the midpoint m of CD are

Mathematics

1 answer:

-BARSIC- [3]2 years ago

6 0

Answer: M(5,2)

Step-by-step explanation:We use the midpoint rule:

We just have to find the arithmetic mean of the x and y-coordinates.

The endpoints of CD are given as C(3,−5) and D(7, 9).

We substitute these values to get:

Therefore the coordinates of the midpoint M of CD are (5,2) and if i'm not good at explaining here ya go :)

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3 years ago

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(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y<br>{-2, 1}<br>{-2, 3}<br>{}

vaieri [72.5K]

Answer:

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Step-by-step explanation:

$\frac{y+4}{2y} +\frac{y-2}{3} =\frac{3y^2+10}{6y}$

Make the fractions have a common denominator.

$\frac{3}{3} (\frac{y+4}{2y}) +\frac{x}{y} (\frac{y-2}{3}) =\frac{3y^2+10}{6y}\\\frac{3y+12}{6y} +\frac{2y^2-4y}{6y} =\frac{3y^2+10}{6y}\\\frac{2y^2-y+12}{6y} =\frac{3y^2+10}{6y}$

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Now, set the equation equal to zero and factor.

$2y^2-y+12=3y^2+10\\-y^2-y+2=0\\(-y-2)(y-1)=0\\\\-y-2=0\\y=2\\\\y-1=0\\y=-1$

The y-values are {-2, 1}

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