5%... since 100% is available..
Answer:
It is B. 15 because the formula for this is 2 (l+w) 15+6=21 21*2=42
Answer:
The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).
N=d+3 because she has 3 more n than d
5n+10d=150
These are givin 5cents in a Nickel so it’s 5n
10 cents in a dime so it’s 10d
We need her to have 150
Now substitute what we know n to be
Into the equation and solve
5(d+3) + 10d = 150
5d + 15 + 10d = 150
15d + 15= 150
15d=135
D=9
Jess had 9 dimes and 12 nickels
Answer:
Step-by-step explanation:
x=-\frac{y-3}{4}+5