Answer:
option a
Step-by-step explanation:
You would first make the fractions improper (making the numerator bigger then the denominator) in order to do that times the denominator with the whole number and add the numerator.
Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions
The question did not spesify the stating value for n.
Assuming, n = 0 is the starting value.
1st term is when n = 0:
f(0) = (0)^2 - 5 = 0 - 5 = -5
2nd term: f(1) = (1)^2 - 5 = 1 - 5 = -4
3rd term: f(2) = (2)^2 - 5 = 4 - 5 = -1
4th term: f(3) = (3)^2 - 5 = 9 - 5 = 4
Therefore, the first 4 terms are: -5, -4, -1, 4.
Answer:
ΔRHS ≅ ΔNKW
Step-by-step explanation:
We are given that, in the triangles RHS and NKW.
∠H = ∠K
Side HS = KW.
∠S = ∠W
Now, using the ASA congruence criteria, which states that when two corresponding angles of the triangles are equal with the included side between them is equal, then both the triangles are congruent.
Hence, according to ASA criteria, ΔRHS ≅ ΔNKW.
Answer: Each bow needs 4.67 yards of ribbon.
Step-by-step explanation:
We know that each roll has 20 yd.
She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:
(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.
With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:
70yd/15 = 4.67 yards
Each bow needs 4.67 yards of ribbon.
