3 years ago

Solve x^2-8x+41=0 for X

Mathematics

1 answer:

andrezito [222]3 years ago

7 0

You get imaginary roots for this equation.

x=4-5i
x=4+5i

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How to solve this problem

solmaris [256]

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2 years ago

-(y + 2) + 8 = 3<br> I’m so confused on this, please send help

Hoochie [10]

Don't be worried friend :)

-(y + 2) + 8 = 3

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3 years ago

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3 years ago

Find the missing part.

sveta [45]

Answer:

The answer is $a = \frac{15}{4}$

Step-by-step explanation:

We have to:

$cos(\theta) = \frac{adjacent\ side}{hypotenuse}$

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$cos(60) = \frac{a}{x}$

We do not know x. But if we take the sine of the angle of 30 degrees and the main triangle we have:

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Then:

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$a = cos(60)\frac{15}{2}$

$a = \frac{15}{4}$

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2 years ago