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IgorC [24]
2 years ago
11

Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written

Mathematics
1 answer:
jarptica [38.1K]2 years ago
5 0

Answer:

b) y = f(x) = -3x+4

Step-by-step explanation:

<u><em>Explanation</em></u>

Given that the equation   9x+3y =12

Let 'x' be an independent variable and 'y' be the dependent variable then the function is of the form

        y = f(x)

      3 y = 12 - 9x

        y = \frac{-9x+12}{3}

      y = -3x+4

The function represented by  y = -3x+4

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Help please, just number 3, thats all im asking, thanks.
Bezzdna [24]

The rectangle that has area 400 has width 10, so its length is 40.

A = LW; L = A/W = 400/10 = 40

The length is 10 + 0.2 = 10.2. The width is 10 + 2 = 12

The multiplication is 10.2 * 12

40.2 * 12 = 40 * 10 + 0.2 * 10 + 40 * 2 + 0.2 * 2

40.2 * 12 = 400 + 2 + 80 + 0.4

40.2 * 12 = 482.4

4 0
2 years ago
Eric conducted a survey of the cars in four parking lots and wrote the following observations:
Veseljchak [2.6K]
Lot 4 had the greatest percentage of blue cars.
3 0
2 years ago
Read 2 more answers
CDEF is a kite and FCE equals 16. Find 2
ELEN [110]

Answer:

m < 3 = 90 - 46 = 44 degrees answer.

Step-by-step explanation:

8 0
3 years ago
Solve for X and Y: <br> Y=2+7x and -2x+6y=-28
Furkat [3]

Answer:

x=-1 and y=-5

Step-by-step explanation:

ሰላም!

Given expressions let them given as two equations

  • y=2+7x....... equation (1)
  • -2x+6y=-28..... equation (2)

Thus, substitute y=2+7x into equation (2)

- 2x + 6(2 + 7x) =  - 28 \\

simplify it

- 2x + 12 + 42x =  - 28 \\ 40x + 12 =  - 28

subtract 12 from both sides

40x + 12 - 12 =  - 28 - 12 \\ 40x =  - 40

divide both sides by 40

\frac{40x}{40}  =  \frac{ - 40}{40} \\ x =  - 1

Therefore, as we get the value of x=-1 substitute it to equation (1) and solve for variable y

y = 2 + 7x \\ y = 2 + 7( -1 ) \\ y = 2 - 7 \\ y =  - 5

To be more sure make a cross check on both of the two expressions

Thus,

1) y=2+7x .... substitute y=-5 and x=-1 and check if it is equal

-5=2+7(-1)

-5=2-5

-5=-5

2)-2x+6y=-28... substitute and check

-2(-1)+6(-5)=-28

2-30=-28... (-a)(-b)=ab

-28=-28

Hope it helps!

6 0
1 year ago
Three Texas drovers met on a highway and began to dicker as follows:
Alik [6]

Answer:

  • Jim's: 7
  • Duke's: 21
  • Hank's: 11

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

  2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

  3(D -14 +1) = (H +14 -1) . . . . Duke's offer

  6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

  2H - J = 15

  3D - H = 52

  6J - D = 21

__

<u>Solution</u>

Adding twice the second equation to the first gives ...

  2(3D -H) +(2H -J) = 2(52) +(15)

  6D -J = 119

Adding 6 times the third equation to this one gives ...

  6(6J -D) +(6D -J) = 6(21) +(119)

  35J = 245

  J = 7

Using this value in the third equation gives ...

  6(7) -D = 21

  42 -21 = D = 21

Using the value of J in the first equation gives ...

  2H -7 = 15

  H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

5 0
2 years ago
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