I hope this helps you
35,894 nearest 36
Answer:
<u>f(x) = 2(x - 2)^2 - 1</u>
<u>vertex: (2, -1)</u>
Step-by-step explanation:
f(x) = 2x^2 - 8x + 7
<em>First, we find the vertex. </em>
x = -(-8)/4 = 2
y = 2(2)^2 - 8(2) + 7 = 2(4) - 16 + 7 = 8 - 9 = -1
vertex: (2, -1)
<em>Second, we write f(x) in vertex form. </em>
<em>we know that h and k have to be 2 and -1. </em>
2x^2 - 8x + 7 = a(x - 2)^2 - 1
<em>Since 8 - 1 = 7, we do this: </em>
f(x) = (2x^2 - 8x + 8) - 1
<em>Factor out the 2 and then factor the polynomial</em>
f(x) = 2(x^2 - 4x + 4) - 1
<em>factors of 4: </em>
1 4
2 2
-1 -4
<u>-2 -2 = -4</u>
<em>the function in vertex for is: </em>
f(x) = 2(x - 2)^2 - 1
ok
Area = 27ft^2
length = l
width = w
Equation
l = 2w + 3
Section A
Area
A = l*w
A = (2w + 3)* w or A = 2w^2 + 3w
27 = 2w^2 + 3w
2w^2 + 3w - 27 = 0 This is the equation
Section B
2w^2 - 6w + 9w - 27 = 0
2w(w - 3) + 9(w - 3) = 0
(w - 3)(2w + 9) = 0
w1 - 3 = 0 2w + 9 = 0
Answer:
(5,3) and (10,6)
Step-by-step explanation:
