Ask question

Ask question

All categories

max2010maxim [7]

3 years ago

7

Certain cooking oil has a density of 0.91 grams per milliliter. Which of the following series of calculations correctly determin

es the mass, in kilograms, of 15 liters of this oil?

1 answer:

pishuonlain [190]3 years ago

3 0

Answer:

Step-by-step explanation:

Here is a picture of the answer, since I couldn't put into words!

You might be interested in

What is the measure <G?

mariarad [96]

Answer:

59°

Step-by-step explanation:

½×(175-57) = ½×118 = 59°

6 0

2 years ago

Can someone please help me with this?

podryga [215]

9514 1404 393

Answer:

x = 3

Step-by-step explanation:

Tangents to a circle from the same point are the same length.

43 -2x = 12x +1

42 = 14x . . . . . . . add 2x-1

3 = x . . . . . . . divide by 14

4 0

2 years ago

What is the answer too 11 - 18s = - 15?

Arlecino [84]

Answer: s = 1.44

Step-by-step explanation:

11 - 18*s = -15

-18*s = -15 - 11

-18*s = -26

18*s = 26

s = 26/18

s = 13/9

s = 1.44

4 0

3 years ago

A music app charges $2 to download the app plus $1.29 per song downloaded. What is the correct equation?

alexandr402 [8]

Answer:

c = 1.29s + 2

Step-by-step explanation:

c represents the total cost

s represents the number of songs downloaded

1.29 represents the cost charged for every song downloaded

2 represents the initial cost to download the app

4 0

2 years ago

The volume of a sphere can be determined by the formula V = 4/3 πr^3, where r is the radius. What is the volume of a sphere with

allochka39001 [22]

Answer:

$V = \frac{99}{7} x^{9}y^{-6}$

Step-by-step explanation:

Given

$V = \frac{4}{3}\pi r^3$

Required

Find V when

$r = \frac{3}{2}x^3y^{-2$

Substitute $\frac{3}{2}x^3y^{-2$ for r in $V = \frac{4}{3}\pi r^3$

$V = \frac{4}{3}\pi * (\frac{3}{2}x^3y^{-2})^3$

Open bracket

$V = \frac{4}{3}\pi * \frac{3}{2}^3 * x^{3*3}y^{-2*3}$

$V = \frac{4}{3}\pi * \frac{27}{8} * x^{9}y^{-6}$

Simplify the fractions

$V = \pi * \frac{9}{2} * x^{9}y^{-6}$

Let

$\pi = \frac{22}{7}$

So:

$V = \frac{22}{7} * \frac{9}{2} * x^{9}y^{-6}$

$V = \frac{11}{7} * \frac{9}{1} * x^{9}y^{-6}$

$V = \frac{99}{7} * x^{9}y^{-6}$

$V = \frac{99}{7} x^{9}y^{-6}$

6 0

3 years ago