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Veronika [31]
3 years ago
6

The agent withdraws 30% of his 10631.25 to pay for a trip to Montego bay, Jamaica. He hotel costs $350 per night for five nights

plus an 8.5% room tax. How much does the agent have remaining
Mathematics
1 answer:
Lana71 [14]3 years ago
8 0
I believe the agent has $1,290.63 left. 

Because... 30% of 10,631.25 is $3,189.38( the exact was 3,189.375 but I rounded up). That's how much the agent has. Since it is $350 a night, 350 x 5= $1,750.00. Then you add the 8.5% to the $1,750 and you get $1,898.75.  That will be the total amount of money he will spend. So you will have to subtract $1,898.75 from $3,189.38 and the amount is $1,290.63. The remaining amount is $ 1,290.63.   I hope this helps :)
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Referring to the Fig. in Question #40, find the unknown<br> length Y.
icang [17]

Answer:

tan30°=7/x

\frac{1}{ \sqrt{3} }  =  \frac{7}{x }  \\ x = 7 \sqrt{3}

cos30°=x/y

\frac{ \sqrt{3} }{2}   =  \frac{7 \sqrt{3} }{y}  \\  \\ 7 \sqrt{3}  \times 2 =  \sqrt{3}  \times y \\ \frac{7 \sqrt{3 }  \times 2}{ \sqrt{3} }  = y \\7 \times 2 = y \\ 14 = y

tell me if it's wrong.

7 0
2 years ago
Read 2 more answers
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
5
Phoenix [80]

Answer:

4:3

Step-by-step explanation:

The computation of the ratio of females to males is shown below

Since it is mentioned that there is 28 students in the class out of which 12 are boys

So, the females are

= 28 - 12

= 16

SO, the ratio of females to males is

16:12

4:3

4 0
3 years ago
Enter the y-intercept of the function
Advocard [28]
The y intercept is (0 , 9)

when x is zero, the number in the y value is the y-intercept
8 0
3 years ago
How do you factor -x^4-5x^2+6
Gekata [30.6K]
(-x-1)(x-1)(x^2+6) 
distribute from there i think? 
math papa website can help with this... im not that good at math

7 0
3 years ago
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