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ankoles [38]
3 years ago
12

G Am 22 10 122 19 3 34 Function in standard form

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

22+10+122+19+3+34

Step-by-step explanation:

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What is the pow of a<br> 4.5 x 10-3 M OH solution?
larisa86 [58]

Answer:

p O H = 2.35

Step-by-step explanation:

7 0
3 years ago
use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r
Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt

If we ask that f has continuous (n+1)th derivative we can apply the mean value theorem for integrals. Then, there exists c between a and x such that

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x

Hence,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .

Thus,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}

and the Taylor theorem with Lagrange remainder is

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}.

Step-by-step explanation:

5 0
3 years ago
Consider the given right triangle. If angle B = 43 degrees and c = 26.7 meters, find a.
Nady [450]

Answer: Side a equals 19.5 metres

Step-by-step explanation: Consider the right angled triangle as shown in the picture attached. The triangle has been drawn with angle measuring 43 degrees, side c (line AB) measuring 26.7 m and side a (line CB) is yet unknown.

A right angled triangle can be solved if at least one side and an angle are available. In this question we shall apply the trigonometric ratios since we have one angle which shall be the reference angle (43°). Also we have an hypotenuse (the side facing the right angle) and an unknown side which is the adjacent (which lies between the right angle and the reference angle).

Cos B = Adjacent/Hypotenuse

Cos 43 = a/26.7

Cos 43 x 26.7 = a

0.7314 x 26.7 = a

19.52714 = a

a ≈ 19.5  (rounded to the nearest tenth)

Therefore the length of side a equals 19.5 metres.

3 0
3 years ago
Read 2 more answers
laura compro un microondas por 216.750 y una lavadora 910.350 si le rebajaron 43.350 en la compra y el resto la paga en 15 plazo
Alecsey [184]
RESPUESTA: Paga $72.250 en cada plazo.
7 0
2 years ago
Pls answer this. its easy but for me nah
zlopas [31]

Answer:

1. acute

2. Right

3. maybe acute

4. obtuse

5. acute

6. obtuse

7. straight

8. obtuse

9. acute

10. obtuse

11. acute

12. acute

13. obtuse

14. obtuse

8 0
3 years ago
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