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2 years ago

Y=x2–2x+5. Write the equation in vertex form.

Mathematics

1 answer:

Crazy boy [7]2 years ago

7 0

Answer:

y = (x - 1)² + 4

Step-by-step explanation:

Given equation:

y = x² - 2x + 5

Complete the square to convert the equation into vertex form:

y = x² - 2x + 1 + 4 =
(x - 1)² + 4

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Please help with math question! This question is stressing me out (View Image)

TEA [102]

To find the volume of this one we need to break it down
now i see half of a cylinder and rectangle:)
but first lets find the volume of the rectangle...
In order to find the Volume of a rectangle we need to use this formula...
Length x width x height
in this case...
length = 10in
width = 6 in
height = 8in
lets solve:)
10 x 6 x 8 = 480
or we write it like this
480in³

now time to find the volume of the half cylinder:)
But first lets remember the volume for a cylinder
Volume = $\pi r^{2} h$
So lets find our measurements
$\pi$ = 3.14
r² = 5² or 25
h = 6
so lets plug in our values just like our formula said:)
3.14 x 25 x 6
now lets easily solve
3.14 x 25 x 6 = 471
now since we found an entire cylinder and we only want half of a cylinder lets divide our answer in half
471 ÷ 2 = 235.5
so we write it like this 235.5units³
But we have to add both of our multiples together so lets do that
Volume of rectangle = 480in³
volume of half sphere = 235.5units³
480 + 235.5 = 715.5
answer = 715.5units³
I hope this helped and everyone learned something new
anyways don't forget to
MARK ME BRAINLIEST! :D

3 0

3 years ago

Given the function, d(t) = 50t, the variable t represents which of the following? Select all that apply. input output function i

Nikitich [7]

Answer:

Input

Independent variable

Step-by-step explanation:

we know that

Independent variables, are the values that can be changed or controlled in a given model or equation

Dependent variables, are the values that result from the independent variables

we have the function

$d(t)=50t$

In this problem

This is a proportional relationship between the variables d and t

The function d(t) represent the dependent variable or the output

The variable t represent the independent variable or input

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3 years ago

Read 2 more answers

What expression can be used to add 7/10 + 13/20

lora16 [44]

0.7+0.65 I’m not sure this is what u were looking for but I hope it helps have a good one

4 0

3 years ago

Identify the graph of the line passing through (0, -3) and (1, 0)

Elena-2011 [213]

Choice B:
The line intersects at both points (0,-3) and (1,0)

(I can not specifically see the number on the grid if there is any but that is what I would put for the answer based on what I see)

If you want me to explain it more I can try to! :)

I hope this helps

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3 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

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3 years ago