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SpyIntel [72]
3 years ago
11

Greatest common divisor of 66 and 90

Mathematics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

6

Step-by-step explanation:

66 / 6 =11

90/6 =15

11 & 15 prime to each other, so 6 is the answer.

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In a volleyball game, a player on one team spikes the ball over the net when the ball is 8 feet above the court. The spike drive
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Answer:

.173 seconds or a negataive

Step-by-step explanation:

Your formula would be

h = -16t^2 - 55t + 10

when it hits the ground h = 0

16t^2 + 55t - 10 = 0

t = (-55 ± √3665)/32 = .173 seconds or a negataive

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OlgaM077 [116]

Answer:

Domain = all real numbers

Range = {-1 [greater than or equal to] y [greater than] Infinity}

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The choices are 40, 120, and 100. Can someone please help?
Phoenix [80]
If I did it right, it is 120
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I don’t understand this problem
Galina-37 [17]

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Step-by-step explanation:

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6 0
3 years ago
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
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