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nikklg [1K]
2 years ago
12

5. A family spends T 600.00 a day for food which is 40% of the

Mathematics
1 answer:
BabaBlast [244]2 years ago
4 0

Answer:

<h3>15%</h3>

Step-by-step explanation:

<h3>First , We will solve their daily Income </h3>

• Income = spends / rate

• Income = 600 / 40%

• Income = 600 / 0 .40%

• Income = 1500

Thus , Their daily Income is 1500 . Now ,We will solve for the rate of the Allowance .

• Rate = spent / Income

• Rate = 225 / 1500

• Rate = 0.15

• Rate = 15%

Therefore, the percent of the family's daily Income of the Allowance of their children's is 15%

<h3>Hope this helps you XD ✌️</h3><h2>Carry on learning !! </h2>

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Solve X + 5 + 6x = 180. What are the steps?
Elenna [48]

Answer:

x=25

Step-by-step explanation:

x+5+6x=180

7x+5=180

7x=175

x=25

3 0
2 years ago
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
In 2013 number of students in a small school is 284.it is estimated that student population will increase by 4 percent
BaLLatris [955]

The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.

Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get

{P}_{n} =284\cdot {1.04}^{n}P

n

=284⋅1.04

n

We can find the number of years since 2013 by subtracting.

\displaystyle 2020 - 2013=72020−2013=7

We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.

\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P

7

=284⋅1.04

7

≈374

The student population will be about 374 in 2020.

5 0
2 years ago
Ms. Pecho currently owes $637.50 simple interest
rusak2 [61]

Answer:

Step-by-step explanation:1

1/2 years which is 1 year and 5 months.

Explanation:

The formula for simple interest is

You can either substitute the given values first and the solve for

T, or you can transpose the formula to have

T as the subject.

T=100xSIPR

T=100 x 637.50

T=100×637.502500×17

T=1.5

As time is always in years, this means it was for

112 years which is 1 year and 5

months

6 0
2 years ago
Show your work <br> Solve multi step equation <br> 4d-3-2d=-15
Fed [463]
I believe this is how you do it

4 0
3 years ago
Read 2 more answers
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