Using decimal multipliers, it is found that a rate of return of 5.2% in the third year will produce a cumulative gain of 16%.
The <u>decimal multiplier</u> for a increase of a% is given by:

In this problem, two increases of 5%, thus:

Another of x, that we want to find, and the result is a increase of 16%, thus:

The three increases(5%, 5% and x%) result in a increase of 16%, thus:



1.052 - 1 = 0.052
A rate of return of 5.2% in the third year will produce a cumulative gain of 16%.
A similar problem is given at brainly.com/question/21806362
Step-by-step explanation:
x² - 2x - 15 = 0
x1 = 5
x2 = -3
Since BD joins the midpoints of two sides of a triangle, it is half the length of the third side, FE.
BD = (1/2)FE = (1/2)(23.5) = 11.75
Answer: B. 11.75
Question:
Veronica is choosing between two health clubs. after how many months will the total cost for each health club be the same? yoga studio a: membership: $24.00 monthly fee: 21.50. yoga studio b: membership: $41.00 monthly fee: $17.25
Answer:
It takes 4 years for the total cost of each club to become equal
Step-by-step explanation:
Given:
For yoga studio A:
membership: $24.00
monthly fee: 21.50.
For yoga studio B:
membership: $41.00
monthly fee: $17.25
To Find:
Number of months after which the total cost for each health club be the same = ?
Solution:
Let x be the number of months of membership, and y be equal the total cost.
For Yoga club A
y = 21.50 x + 24
For Yoga club B
y = 17.25 x + 41.00
we know that the prices, y , would be equal, we can set the two equations equal to each other.
21.50 x + 24 =17.25 x+ 41.00
Grouping the like terms,
21.50x - 17.25 x= 41.00
- 24
4.25x=17
x=
x = 4
Answer:

Step-by-step explanation:
Since, By the given diagram,
The side of the inner square = Distance between the points (0,b) and (a-b,0)


Thus the area of the inner square = (side)²


Now, the side of the outer square = Distance between the points (0,0) and (a,0),


Thus, the area of the outer square = (side)²

Hence, the ratio of the area of the inner square to the area of the outer square
