Answer:
Obtuse
Step-by-step explanation:
acute is below 90° and a triangle adds up to 180° so it would have to be obtuse
X/5+11=0 is the expression or x+y/5+11=0 is also an expression
![f(x)=x^2-4x+3](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-4x%2B3)
a=1, b=-4, c=3
If the vertex has coordinates (2;-1)(p=2,q=-1) we can write vertex form of a parabola equation:
![f(x)=a(x-p)^2+q](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-p%29%5E2%2Bq)
![f(x)=1(x-2)^2-1](https://tex.z-dn.net/?f=f%28x%29%3D1%28x-2%29%5E2-1)
We need to put (x-2) at the place of (x) in f(x) equation to get g(x)
![g(x)=1[(x-2)-2]^2-1](https://tex.z-dn.net/?f=g%28x%29%3D1%5B%28x-2%29-2%5D%5E2-1)
![g(x)=(x-2-2)^2-1](https://tex.z-dn.net/?f=g%28x%29%3D%28x-2-2%29%5E2-1)
![g(x)=(x-4)^2-1](https://tex.z-dn.net/?f=g%28x%29%3D%28x-4%29%5E2-1)
So:
p=4, q=-1
Vertex of the parabola defined by g(x)=f(x-2) has the vertex at
:)