All categories

3 years ago

Please help I need it asp

Mathematics

2 answers:

sergeinik [125]3 years ago

6 0

Answer:

Step-by-step explanation:

DedPeter [7]3 years ago

5 0

Answer:

Step-by-step explanation:

H is an exterior angle. It is equal to the two given angles.

H = 65 + 50

H = 115

G and H are supplementary (they equal 180)

G + H = 180

G + 115 = 180

G = 180 - 115

G = 65

J is vertically opposite G. G and J are equal.

J = G

J = 65

You might be interested in

I need help with these 3 questions plz

malfutka [58]

Answer:

16. C

17. D

18. A

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Mrs. Clark wants to plant rose bushes along the front of her house. The length she wants to cover is 13 feet, and she wants to a

larisa86 [58]

Answer:

Mrs Clark spends in total $119 on rose bushes.

Step-by-step explanation:

Here, the total length that needs to be covered = 13 ft

The distance between 2 consecutive rose pant = 2 ft

Cost of planting each bush = $17

Now, if we plant first plant at 1 feet,

Then the second bush will be planted at a distance of 2 ft + 1 ft = 3 ft

Third bush = Second Bush + 2 ft = 3 ft + 2 ft = At 5 ft

Fourth bush = Third Bush + 2 ft = 5 ft + 2 ft = At 7 ft

Fifth bush = Fourth Bush + 2 ft = 7 ft + 2 ft = At 9 ft

Sixth bush = Fifth Bush + 2 ft = 9 ft + 2 ft = At 11 ft

And, lastly Seventh bush = Sixth Bush + 2 ft = 11 ft + 2 ft = At 13 ft

So, as to cover a total of 13 ft, 7 bushes are planted in total which are 2 ft apart from one another.

Now, cost of planing 7 rose bushes = 7 x ( Cost of planting 1 rose bush)

= 7 x ($17) = $119

Hence, Mrs Clark spends in total $119 on rose bushes.

5 0

3 years ago

5 degrees below zero

xz_007 [3.2K]

Answer:

5 degrees below zero = -5 degrees

3 0

4 years ago

Read 2 more answers

Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound

Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

$\dag{\underline{\boxed{\sf{C.I = P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1}}}}$

<u>Where</u>

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

$\textsf{ \underline{Solution-}}\\$

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

$\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}$

Substituting the given values

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}$

$\quad{: \implies{\sf{1290 = P \times {0.3225}}}}$

$\quad{: \implies{\sf{\dfrac{1290}{0.3225} = P}}}$

$\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000} = P}}}$

$\quad{: \implies{\sf{\dfrac{12900000}{3225} = P}}}$

$\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}} = P}}}$

$\quad{: \implies{\sf{Rs.4000 = P}}}$

$\quad{\dag{\underline{\boxed{\tt{\blue{Principle} = \purple{Rs.4000 }}}}}}$

$\begin{gathered}\end{gathered}$

<u>Hence,</u>

The sum (Principle) is Rs.4000.

3 0

3 years ago

Limit of x^2-81/x+9<br> As x goes toward -9

Semmy [17]

Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18

7 0

3 years ago