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alekssr [168]
2 years ago
7

Tech a says that analog signals are continuously variable signals. Tech b says that digital signals are direct on/off signals wi

th no in-between transition. Who is correct?.
SAT
1 answer:
Blababa [14]2 years ago
7 0

The person that is correct based on the two statements made by Tech A and Tech B is;

Both of them.

An analog signal is one that is continuous in both instances of time and amplitude.

Now, in the real world examples of Analog signals are; current, voltage, temperature, pressure, light intensity etc.

Meanwhile, the digital signals are those that contain the digital values which are usually converted at specific instances from the analog signal.

This means that they can have only 2 states which is On or Off.

Read more about analogue and digital signals at; brainly.com/question/15084481

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In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). Nancy has not studied for the exa
maria [59]

Using the binomial distribution, it is found that there is a 0.6836 = 68.36% probability that she guesses at least one right.

For each question, there are only two possible outcomes, either she gets it right or she does not get it right. The probability of getting a question right is independent of any other question, hence the <em>binomial distribution</em> is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 5 questions, hence n = 5.
  • For each question, she guesses one out of 4 options, hence p = 1/4 = 0.25.

The probability that she guesses at least one right is:

P(X \geq 1) = 1 - P(X = 0)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.25)^{0}.(0.75)^{4} = 0.3164

Hence:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3164 = 0.6836

0.6836 = 68.36% probability that she guesses at least one right.

You can learn more about the binomial distribution at brainly.com/question/24863377

8 0
2 years ago
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Answer:

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2 years ago
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At an ocean depth of 20 meters, a buoy bobs up and then down 2 meters from the ocean's depth. Four seconds pass from the time th
stiv31 [10]

The first and second coordinate points of the sine graph are;

(0, 20) and (2, 22)

<h3>Sine Graph expression</h3>

The general formula we will use to plot the graph is;

y = [Asin (2πx/t)] + ∅      (Note that sin is in radians)

where;

A is amplitude

t is period

∅ is phase shift

We are told that the buoy bobs up and then down 2 meters from the ocean's depth. This means that;

Amplitude; A = 2

Now, Four seconds pass from the time the buoy is at its highest point to when it is at its lowest point. Thus;

Period = 2 * 4 = 8 seconds

Assume at x = 0, the buoy is at normal ocean depth. Thus;

Phase shift; ∅ = 20

Thus, we have;

y = [2sin((2πx/8)] + 20  

At x = 0, we have;

y = [2sin((2π*0/8)] + 20  

y = 0 + 20

y = 20

Thus, first point is; (0, 20)

Since the second point must be a maximum or minimum value on the graph closest to the first point, then we put 2 for x to get the coordinate of the second point;

y = [2sin((2π*2/8)] + 20  

y = [2sin((2π*2/8)] + 20  

y = [2sin(π/2)] + 20  

In radians, sin(π/2) = 1. Thus;

y = (2 * 1) + 20

y = 22

Second point is (2, 22)

Using the first and second point coordinates, we will use sine tool to graph the function as attached below.

Read more about sine graph at; brainly.com/question/18055768

3 0
2 years ago
C=
Blizzard [7]

Answer:

Whatever you think the answer is, go with it. Believe that you have the answer correct, and you will.

Explanation:

Believe in yourself.

3 0
3 years ago
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