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maxonik [38]
2 years ago
7

Pls help me I’m trying my best but it’s too hard

Mathematics
1 answer:
bekas [8.4K]2 years ago
3 0

Answer:

Step-by-step explanation:

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PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!<br><br> What is the expression in radical form?
Charra [1.4K]

(4x^{3}y^{2})^\frac{3}{10} =\sqrt[10]{4^{3}x^{9}y^{6}} =\sqrt[10]{64x^{9}y^{6}}

7 0
3 years ago
Will there be an inauguration in 2046? hurry plz
joja [24]

Answer:

MAYBEEEE WHO KNOWSSS

Step-by-step explanation:

7 0
3 years ago
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Simplify by using the distributive property 5 ( 2x - 5 )
drek231 [11]
Hello!

The problem has asked that we simplify the given expression using the Distributive Property. The Distributive Property states the following:

a(b + c) = ab + ac
a(b – c) = ab – ac

In this case, we’ll use the second of the two formulas listed above. Let’s begin by inserting any known values given in the original problem:

a(b – c) = ab – ac
5(2x – 5) = 5(2x) – 5(5)

Now simplify the right side of the equation:

5(2x) – 5(5) = 10x – 25

We have now proven that 5(2x – 5) is equal to 10x – 25. Therefore, the correct answer is C.

I hope this helps!

3 0
4 years ago
Read 2 more answers
What logarithmic equation has the same solution as x-4=2^3
kumpel [21]

What logarithmic equation has the same solution as x-4=2^3

Solution:

x-4=2³

x-4=2*2*2

x-4=8

TO solve for x, Let us add 4 on both sides

x-4+4=8+4

x+0=12

So, x=12

But, x=12 is not a logarithmic equation and there are no options

So, an equation like, x=㏒ 10^{12}

As log has base 10,

So, x=㏒ 10^{12}=12

So, logarithmic equation like x=log 10^{12} has same solution as x-4=2³

5 0
3 years ago
Read 2 more answers
Use differentials to estimate the amount of material in a closed cylindrical can that is 60 cm high and 24 cm in diameter if the
alexira [117]

Answer:

dV=542.9 cm^{3}    

Step-by-step explanation:

Let's start with the equation of the volume of a cylinder:

V=\pi r^{2}*h

Where:

  • r is the radius of the cylinder (r=D/2=24/2=12 cm)
  • h is the high of the cylinder (h = 60 cm)

We can us partial derivatives to find the differential of this volume. So we will have:

dV=\frac{\partial V}{\partial r}dr+\frac{\partial V}{\partial h}dh (1)

Now:

\frac{\partial V}{\partial r}=2\pi r*h=2\pi 12*60=4523.9 cm^{2}

\frac{\partial V}{\partial h}=\pi 12^{2}=452.4 cm^{2}

dr is a differential of the radius, so in our case it is 0.1 cm and dh, differential of the high, is 0.1*2 cm. We multiply by 2 because we need to consider the top and the bottom of the cylinder.

Now we just need to put all of this definitions in the equation (1).

dV=4523.9*0.1+452.4*0.2=542.9 cm^{3}    

I hope it helps you!

6 0
4 years ago
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