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Vilka [71]
3 years ago
10

two angles are supplementary the measure of one angle is 116 degrees what is the measure of the other angle?

Mathematics
2 answers:
Rainbow [258]3 years ago
6 0
The measure of the other angle is 64 degrees bc supplementary angles add up to 180 and 116 plus 64 is 180
amm18123 years ago
4 0

Answer:

55

Step-by-step explanation:

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Helpppp pleasssss!!!!
DaniilM [7]

Answer:

Step-by-step explanation:

A)  

attached , I used g o o g l e draw.

B)

0.8 m  = 80 cm    =800 mm /50 = 16 mm

C)

bed = 4cm x 3cm  

4cm*50= 200 cm = 2 m  

3cm*50 = 150 cm = 1.5 m

8 0
3 years ago
Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward
Andru [333]
Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k

-24=3a
divide both sides by 3
-8=a

-2=a+k
-2=-8+k
add 8 to both sides
6=k

the equation is
y=-8(x-4)^2+6
3 0
3 years ago
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

4 0
2 years ago
Sin cos and tan help
Nikitich [7]
Sin(B) = opp/hyp = 32/40 = 0.8
cos(B) = adj/hyp = 24/40 = 0.6
tan(B) = opp/adj = 32/24 = 1.33 (repeating)
7 0
2 years ago
The experimental factor that is manipulated; the variable whose effect is being studied is called ____________
lorasvet [3.4K]

Answer:

The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>

Step-by-step explanation:

Consider the provided information.

In an experiment, the two principal variables are the independent and dependent variable.

An independent variable is the variable that is altered or controlled to test the effects on the dependent variable in a scientific experiment.

The variable which is tested and measured in a scientific experiment is a dependent variable.

From the above definition: The experimental factor that changed or controlled in a scientific experiment is called independent variable.

Therefore, the complete statement is: The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>

8 0
2 years ago
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