First write the balanced equation of this reaction:
2H2 + O2 —> 2H2O
mol of H2= 0.60 gH2/2.02 gH2 = 0.297 mol
There are 2 mol of H2 for every 2 mol of H2O so the number of mol of H2 is equal to the number of mol of H2O.
g of H2O = 0.297 mol H2O • 18.02 gH2O = 5.35 g H2O
Do the same thing for O2:
mol of O2 = 4.8 gO2/32.0 gO2 = 0.15 mol of O2
There is 1 mol of O2 for every 2 mol of H2O so multiply 0.15 • 2 to get the number of mol of H2O
g of H2O = 0.30 mol H2O • 18.02 gH2O = 5.41 g H2O
The correct answer is 5.35 g H2O (or 5.4 g if checking significant figures) because O2, in this case, is the limiting reactant of this reaction.
Answer:
0.028kg
Explanation:
We were given 2.6 × 1023 molecules of SO 2 That means that
N = 2.6 × 1023 molecules
Use
n (number of moles) = N
NA (Avogadro's constant)
to get
n =2.6×1023 molecules
6.02 ×1023 molecules/mol = 0.432 moles
Now use
m = n × M (molar mass)
to get
m = 0.432 mol × 64.066 g/mol = 27.677 g
So
m (in kilograms) = 27.677 g
103 g/kg = 0.028 kg
Answer:
the answer is 5⁷
Explanation:
it is 5 to the power of 7 because 5 is it base and then the 4 and 5 get added to get ur exponent
C. Water molecules have a positive charge on one end and a negative charge on
the other.
The answer is conductors
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