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Mashcka [7]
3 years ago
7

Which two structures play direct roles in permitting bacteria to adhere to each other or to other surfaces?

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer: capsule and fimbriae

Explanation:

Many prokaryotes have sticky outermost layer called the capsule.It is made up of polysaccharides and it helps them clinging to each other or to other surfaces around them.It also helps prevent the cell from drying out.

Fimbriae,also known as attachment pilus,used by bacteria to adhere to one and other,animal cells or to any inanimate objects.

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why do liquids flow? the particles are tightly packed together the particles do not move the particles vibrate the particles are
tangare [24]
The particles are quite tightly packed together but still have enough room to be able to move and flow, their bonds aren't as strong as a solids are
3 0
3 years ago
Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m
faust18 [17]

Answer:

56°

Explanation:

First calculate a:

a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}

The interplanar spacing can be calculated from:

d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}

The diffraction angle is determined from:

\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476

Solve for \theta

\theta=\sin ^{-1}(0.476)=28^{\circ}

The diffraction angle is:

2 \theta=2\left(28^{\circ}\right)=56^{\circ}

4 0
3 years ago
Can anyone help me part 1
valina [46]
I can help you with part 1
8 0
3 years ago
What is 316 Kelvin in Celsius ?
ss7ja [257]

Answer:

42.85 Celsius

5 0
3 years ago
What is the mass of 4.5 x 10^22 molecules of hydrogen peroxide (H2O2)? Show your work in the space below.
valentinak56 [21]

Given :

Number of molecules of hydrogen peroxide, N = 4.5 × 10²².

To Find :

The mass of given molecules of hydrogen peroxide.

Solution :

We know, 1 mole of every compound contains Nₐ = 6.022 × 10²³ molecules.

So, number of moles of hydrogen peroxide is :

n = \dfrac{N}{N_a}\\\\n = \dfrac{4.5\times 10^{22}}{6.022\times 10^{23}}\\\\n = 0.0747 \ moles

Now, mass of hydrogen peroxide is given as :

m = n × M.M

m = 0.0747 × 34 grams

m = 2.54 grams

Hence, this is the required solution.

6 0
3 years ago
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