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4 years ago

Materials that don't allow electrons to flow freely are called _____.

Chemistry

2 answers:

krek1111 [17]4 years ago

8 0

insulators

Answer for apex

EastWind [94]4 years ago

4 0

The answer is conductors

You welcome : )

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Your TLC results for ortho-hydroxyacetophenone versus para-hydroxyacteophenone will indicate that one compound is significantly

Sloan [31]

Answer:

2-hydroxy

Explanation:

The 4-hydroxy has a reduced dipole because its two electronegative substituents give it a dipole in opposite directions. On the other hand the 2-hydroxy has dipoles that add together.

7 0

4 years ago

Convert 16 inches to feet

MrRa [10]

There is 12 inches in 1 foot.

Divide 16 with 12 to get feet

16/12 = ~1.33 (rounded)

1.33 is your answer

hope this helps

5 0

4 years ago

Read 2 more answers

When combined, two gases have a pressure of 75.54 atm. If one has has a pressure of 2.90 atm, what is the pressure of the second

nataly862011 [7]

Answer:

The pressureof the secondone is 2.5 atm

Explanation:

hope this helps

4 0

3 years ago

H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles

abruzzese [7]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$H_2(g)+F_2(g)\rightarrow 2HF(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]$

We are given:

$\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = $\frac{-14.1}{1}\times 2.20=-31.02J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0

3 years ago

The mass of any amount of a solid, liquid, or gas relative to its volume is called its ____________.

zheka24 [161]

Eazy, it’s called density

I’m only in 8th grade science you know

8 0

3 years ago