We have that, how long it will take for Liu to catch Mariel is mathematically given as
t=3.076s
From the question we are told
Mariel and Liu are running a long-distance race. Mariel runs at a rate of 5.4 m/s, and Liu runs at a rate of 7.6 m/s. If Mariel has a 20 m head start, how long will it take for Liu to catch Mariel?
Generally the equation for the Average speed is mathematically given as

Therefore
How long it will take for Liu to catch Mariel is mathematically given as

t=3.076s
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The answer is like $35,800 or something like that. Very close approximate answer
Apply the Pythagorean theorem
a^2 + b^2 = c^2
a = 5, b = 13.
5^2 = 25, 13^2 = 169
25 + 169 = 194
square root 194 = 13.928, rounded to nearest foot = 14 ft.
The minimum ladder length required to reach the top of the wall = 14 ft.
7 x 110 = 7(50 + 60) = 350 + 420 = 770