<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
Answer:
Step-by-step explanation:
B.) would be correct
(x,y)
x=-5
y=x+4
y=(-5)+4
y=-1
(-5,-1)
Answer:
x=-4
x=4
Step-by-step explanation:
We can factor x^2 -16 = 0 by recognizing that it is a difference of squares. That means we can factor the equation to (x-4)(x+4) = 0. By using the Zero Product Property we know that either (x-4) or (x+4) is equal to 0. That means that x either equals -4 or 4.