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julia-pushkina [17]
3 years ago
10

End of semester test geometry Semester A question 11

Mathematics
1 answer:
nalin [4]3 years ago
5 0

Answer: Step 1 <--------

Step-by-step explanation:

No point E only ABC

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What is the slope of the line that passes through the points M (-3,5) and N (1,8)
zysi [14]

Answer:

m=3/4

Step-by-step explanation:

See the attached above.

Hope it helps :)

4 0
3 years ago
Need help with this math question (pic included)
Kamila [148]

Answer:

8

Step-by-step explanation:

If the only zero for this function is at x = - 4 it looks like this:

f(x)  = (x+4)(x+4)        =    x^2 +8x + 16      <u>   so j = 8 </u>

6 0
2 years ago
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Which of the following is equivalent to “the product of 2 and 3 is increased by 7”?
trasher [3.6K]
A. 2(3)+7

product is multiplication
increased is addition
8 0
3 years ago
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
3 years ago
The length of a rectangle is 7 inches longer than it is wide. If the area is 20 square inches, what are the dimensions of the re
Arada [10]

Area of a rectangle is length x width.

Let the width = x

The length would be x +7. ( 7 inches longer than the width)

Area = 20

Set up the formula:

20 = x * x+7

Simplify the right side:

20 = x^2 + 7x

Subtract 29 from both sides:

X^2 + 7x -20 = 0

Solve using the quadratic equation

X = -b + sqrt(b^2 -4ac) / 2a

X = -7 + sqrt(7^2-4(1)(-20) / 2(1) (exact answer)

X = 2.178908 ( as a decimal)

The width is 2.178907 inches (round as needed)

The length would be 9.178907 inches ( round as needed.)

Depending on how you round, when you multiply them together you get approximately 20 square inches.

4 0
4 years ago
Read 2 more answers
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