Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
<span>
base1= 158.802
</span>
<span>
base2=596.008
the distance travelled = 596.008 - 158.802
= 438 m</span>
<span>$125 is to be paid during the 6th month.</span>
Answer:
14.25 hours
Step-by-step explanation:
Four tires = 3/4 of an hour
=> 1 car = 3/4 of an hour
=> 19 cars = ?
=> If 1 = 3/4
=> 19 = 3/4 x 19
=> 3/4 x 19
=> 57/4
=> 14.25 hours
So, it would take 14.25 hours for 19 car's tires to be changed.
We are unable to answer this question without being able to see the graph.
