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evablogger [386]
3 years ago
13

10. A line passes through the points (-3,8) and

Mathematics
1 answer:
Vilka [71]3 years ago
6 0

Answer:

a.-3

b. y=-3x-1

c. y=-3x-1

d. 3x+y=-1

Step-by-step explanation:

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Step-by-step explanation:

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NO LINKS!!!! Find the equation of the circle below​
inysia [295]

Answer:

(x+3)^2+(y-2)^2=9

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

From inspection of the diagram, the center of the circle <em>appears</em> to be at point (-3, 2), although this is not very clear.  Therefore, a = -3  and  b = 2.

Substitute these values into the general form of the equation of a circle:

\implies (x-(-3))^2+(y-2)^2=r^2

\implies (x+3)^2+(y-2)^2=r^2

Again, from inspection of the diagram, the <u>maximum vertical point</u> of the circle appears to be at y = 5.  Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

\implies (x+3)^2+(y-2)^2=3^2

Therefore, the final equation of the given circle is:

\implies (x+3)^2+(y-2)^2=9

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