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Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav

Furkat [3]

Answer:

There is no significant evidence that p1 is different than p2 at 0.01 significance level.

99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

$H_{0}$ : p1-p2=0

$H_{a}$ : p1-p2≠0

Test statistic can be found using the equation:

$z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of the common attribute in population1 ( $\frac{16}{30} =0.533$ )

p2 is the sample proportion of the common attribute in population2 ( $\frac{1337}{1900} =0.704$ )

p is the pool proportion of p1 and p2 ( $\frac{16+1337}{30+1900}=0.701$ )

n1 is the sample size of the people from population1 (30)

n2 is the sample size of the people from population2 (1900)

Then $z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}}$ ≈ 2.03

p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2± $z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}}$ where

z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704± $2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}}$ ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0

3 years ago

Heidi spent a total of $60 on clothing items she bought 2 pairs of shorts for 10 dollars each she bought some t-shirts for 4 eac

lisov135 [29]

Answer:

2 pair shorts and for t-shirts and sandals possible cases are

1 t-shirt and 3 sandals or

4 t-shirts and 2 sandals or

7 t-shirts and 1 sandals.

Step-by-step explanation:

Total money spent by Heidi on the clothing items is $60.

Now , she bought 2 pairs of short for $10 each , so, the money spent on shorts will be $20.

Thus money for other stuffs should be $40.

Let she bought x t-shirts for $4 each , thus money spent on t-shirts will be 4x dollars.

Also let she bought y sandals for $12 each , so money spent on sandals will be 12y dollars .

Thus , 4x + 12y = 40. (since 40 dollars were remaining for other clothing

items)

So, x + 3y = 10.

So, the possible cases are 1 t-shirt and 3 sandals or

4 t-shirts and 2 sandals or

7 t-shirts and 1 sandals.

7 0

3 years ago

Find the common difference of the arithmetic<br> sequence 4, 10, 16,

DIA [1.3K]

Answer:

10it is 10

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help me. What is the y intercept of the graph shown below?

natta225 [31]

Answer:

(0,2)

Step-by-step explanation:

the point where Oy intercepts the graph has x=0 and y= f(0)

so this is (0,2)

7 0

3 years ago

Imagine that you have a very large barrel that contains tens of thousands of M&M's. According to the official M&M websit

Finger [1]

Answer:

(A)20%, 20%, 20%, 20%, 20%

Step-by-step explanation:

We are told that 20% of the M&M's produced by the Mars Corporation are Orange in color. If 5 students take a random sample of 50 M&M's, the most plausible percentage of orange candies that will be obtained is:

20%, 20%, 20%, 20%, 20%

This is as a result of the fact that in research experiments, a sample is a representation of the whole. Any result which holds for a random sample should hold for the total population and vice versa.

5 0

3 years ago